Answer: 0.85075J/g.K
Explanation:
Mass of the material = 100g
Energy (Q) = 5104.5J
T1 = 20°C = 293K
T2 = 80°C = 353K
Formula for heat energy (Q) = mc ∇T
Q = mc∇T
∇T = T2 - T1
∇T = 353K - 293K = 60K
Q = mc∇T
C = Q / m∇T
C = (5104.5) / (100 * 60)
C = 0.85075 J/gK
The specific heat capacity of the material is 0.85075J/gK.
The new concentration of the solution is 0.016 M
<h3>Dilution</h3>
From the question, we are to determine the concentration of the new solution prepared from question 4.
NOTE: Question is provided below
From question 4, the concentration of the sodium chloride solution is 0.200M
Now, to determine the new concentration,
Using the dilution law
C₁V₁ = C₂V₂
Where
C₁ is the initial concentration
V₁ is the initial volume
C₂ if the final concentration
and V₂ is the final volume
Then,
C₁ = 0.200 M
V₁ = 10.00 mL
C₂ = ?
V₂ = 125.00 mL
Then,
0.200 × 10.00 = C₂ × 125.00
C₂ = 0.016 M
Hence, the new concentration of the solution is 0.016 M
Question 4:
Calculate the amount of solid sodium chloride needed to make 200.00 mL of a 0.200 M solution
Learn more on Dilution here: brainly.com/question/24881505
The appropriate response is high. The best approach to consider it is those molecules have more vitality than the normal and it is unequivocally those higher enthusiastic ones that have enough vitality to break the intra-molecular forces and leave. By the way this is the reason when we sweat we chill off - the most enthusiastic molecules vanish diverting warmth.
Answer:
Kr has one more electron than br and so, the nuclear charge increase, which means the nuclear attraction between the nucleus and outer most electron will increase and so will be harder to remove the electron from Kr than Br, so Kr has higher 1st ionisation.
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No, the dilution does not change the number of moles dissolved
Explanation:
We can see that,
The molarity of the solution was 0.50 M
The volume of the solution is 10 ml.
No of moles of the solute was= volume * concentration
= 10 X 10^-3* 0.50
= 5*10^-3 moles
When the solution is diluted from 10 ml to 100ml, the molarity or concentration changes but number of moles remains constant.
The molarity of 100 ml solution will be
c=n/V
= 5*10^-3*/100*10^-3
= 0.05
when the solution is diluted to 100ml from 10 ml molarity changes from 0.5M TO 0.05 M
