All categories

2 years ago

When the products of a reaction have less energy than the reactants:

Chemistry

2 answers:

abruzzese [7]2 years ago

7 0

The answer is that the reactants lost internal energy

iragen [17]2 years ago

4 0

The answer is C <span>The reactants lost internal energy.</span>

You might be interested in

Please help make sure its correct thanks

Wewaii [24]

The empirical formula of metal iodide : CoI₃(Cobalt(III) Iodide)

<h3>Further explanation</h3>

13.02 g sample of Cobalt , then mol Co(MW=58.933 g/mol) :

$\tt mol=\dfrac{mass}{Ar}=\\\\mol=\dfrac{13.02~g}{58.933}\\\\mol=0.221$

Mass of metal iodide formed : 97.12 g, so mass of Iodine :

$\tt =mass~metal~iodide-mass~Cobalt\\\\=97.12-13.02\\\\=84.1~g$

Then mol iodine (MW=126.9045 g/mol) :

$\tt \dfrac{84.1}{126.9045}=0.663$

mol ratio of Cobalt and Iodine in the compound :

$\tt 0.221\div 0.663=1\div 3$

5 0

2 years ago

Chuẩn Độ 15 ml dung dịch CH3COOH 0,2 m bằng dung dịch NaOH 0,2 m

mina [271]

Answer:

<h3>I don't know what is the answer of your question sorry never mind..</h3>

Explanation:

<h3>And please marks me as brainliest... </h3>

3 0

2 years ago

Consider the reaction of 19.0 g of zinc metal with excess silver nitrate to produce silver metal and zinc nitrate. The reaction

Alexeev081 [22]

Answer:

14.5 g silver

Explanation:

This is a problem using the stoichiometry of the reaction. First thing we need is the balanced equation:

Zn + 2 AgNO3 ----------------------- 2 Ag + Zn(NO3)2

We know that 14.6 g of Zn did not reacted, then we can calculate the amount of Zn reacted and do the calculation given the above reaction.

amount Zn reacted: 19.0 -14.6 g Zn = 4.4 g Zn

atomic weight of Zn: 65.37 g/mol

mol Zn reacted: 4.4 g Zn x ( 1 mol Zn/ 65.37 g Zn) = 0.067 mol Zn

We know from the balanced equation that moles of Ag are produced from 1 mol Zn therefore the mol of Ag produced are:

0.067 mol Zn x 2 mol Ag/ 1mol Zn = 0.135 mol Ag

and the mass of silver then will be given by multiplying by the atomic weight of silver:

0.135 mol Ag x 107.9 g/mol = 14.5 g Ag

4 0

3 years ago

The distance between the centers of the two oxygen atoms in an oxygen molecule is 1.21 x 10-8 cm. What is this distance in inche

Sergio [31]

Answer:

$d=4.75\times 10^{-9}\ \text{inches}$

Explanation:

Given that,

The distance between the centers of the two oxygen atoms in an oxygen molecule is $1.21\times 10^{-8}\ cm$ .

We need to convert this distance in inches.

We know that,

1 cm = 0.393 inches

We can solve it as follows :

$1.21\times 10^{-8}\ cm=0.393\times 1.21\times 10^{-8}\\\\=4.75\times 10^{-9}\ \text{inches}$

So, the distance between the centers of the two oxygen atoms is $4.75\times 10^{-9}\ \text{inches}$ .

5 0

2 years ago

Which compound would you expect to be soluble in the nonpolar solvent carbon disulfide?

ch4aika [34]

Answer:

hexane C6H14

IS YOUR ANSWER

Explanation:

I HOPE IT HELPS MATE

MARK ME BRAINLIEST PLS

I WILL ALWAYS HELP YOU UNDERSTANDING YOUR ASSINGMENTS

HAVE A GREAT DAY

#CAPTAINPOWER :)

8 0

2 years ago