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natali 33 [55]
3 years ago
6

The name of the METAL in an ionic compounds does not change True or False

Chemistry
1 answer:
WITCHER [35]3 years ago
4 0

。☆✼★ ━━━━━━━━━━━━━━  ☾

This is a true statement.

Here are some examples of ionic compounds:

Sodium chloride

Potassium fluoride  

Have A Nice Day ❤  

Stay Brainly! ヅ  

- Ally ✧  

。☆✼★ ━━━━━━━━━━━━━━  ☾

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According to the Brönsted-Lowry theory, an acid is ___
Zigmanuir [339]

Answer:

is a substance which donates an H^+ or a proton

8 0
2 years ago
Read 2 more answers
Which acide will have more strength<br>out of two acids of pH<br>value 2<br>and 5 why<br>​
gladu [14]

Ph 2 will ahve more strength due to the fact that its more acidic compared to pH 5.

the lower the number of a pH, the more it is heading towards being acidic, but the higher the number, the more it heads towards being an alkali. here is a ppt i made along time ago. hope it can help you . have a nice day

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5 0
3 years ago
When a 5.00-g metal piece, A, was immersed in 38.0 mL of water, the water level rose to 50.0 mL. Similarly, when a 5.00-g metal
Mnenie [13.5K]

Answer:

A is denser than B as it's volume for the same mass is smaller.

Explanation:

Hello.

In this case, we first need to take into account that the density of each metal A and B is computed by dividing the mass over the volume of each metal which is actually computed by substracting the volume of water from the volume of the water and the solid:

V_A=50.0mL-38.0mL=12.0mL\\\\V_B=60.0mL-38.0mL=22.0mL

Next, we compute the densities as shown below:

\rho_A=\frac{m_A}{V_A}=\frac{5.00g}{12.0mL}=0.42g/mL\\  \\\rho_B=\frac{m_B}{V_B}=\frac{5.00g}{22.0mL}=0.23g/mL

In such a way, A is denser is B as it's volume for the same mass is smaller.

Best regards.

4 0
3 years ago
6. The Earth’s electric field is directed vertically downward; at the ground level its strength is E = 130 N/C, and at an altitu
Alexxx [7]

Answer:

5.31x10⁻⁶ C

Explanation:

The cube is located 100 m altitude from the ground, so the superior face is at 100m and has E = 70 N/C, and the inferior face is at the ground with E = 130 N/C.

The electric field is perpendicular to the bottom and the top of the cube, so the total flux is the flux at the superior face plus the flux at the inferior face:

Фtotal = Ф100m + Фground

Where Ф = E*A*cos(α). α is the angle between the area vector and the field (180° at the topo and 0° at the bottom):

Фtotal = E100*A*cos(180°) + Eground*A*cos(0°)

Фtotal = 70A*(-1) + 130*A*1

Фtotal = 60A

By Gauss' Law, the flux is:

Фtotal = q/ε, where q is the charge, and ε is the permittivity constant in vacuum = 8.854x10⁻¹² C²/N.m²

A = 100mx100m = 10000 m²

q = 60*10000*8.854x10⁻¹²

q = 5.31x10⁻⁶ C

8 0
3 years ago
What mass of O2 is needed to completely react with 500 g of Fe
Zina [86]

Answer:

solution given:

Explanation:

4Fe +3O2------------>2Fe2O3

4mole. 3mole. 2 mole

224g. 96g. 320g

we have

224 g of fe needed to react completely with 96 g of O2

500g of fe needed to react completely with

96 ×500/224=214.3g of O2

214.3g of O2 is a required answer.

8 0
2 years ago
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