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3 years ago

Drag the tiles to the boxes to form correct pairs.

Chemistry

2 answers:

strojnjashka [21]3 years ago

8 0

Answer:

1) Proportions decreased as it reacted with other elements to form nitrogen. -AMMONIA

2) Proportions decreased as this lighter gas was blown away by solar winds.- HYDROGEN

3) Proportions increased as this gas was released through volcanic eruptions. -WATER VAPOR

4) Proportions increased as plants released this gas into the atmosphere.- OXYGEN

5)Proportions decreased as plants used this gas during photosynthesis.- CARBON DIOXIDE

Explanation:

IT'S RIGHT 100 %

77julia77 [94]3 years ago

5 0

Answer:

Oxygen - Proportions increased as plants released this gas into the atmosphere.

Water Vapor - Proportions decreased as this lighter gas was blown away by solar winds.

Hydrogen - Proportions increased as this gas was released through volcanic eruptions.

Ammonia - Proportions decreased as it reacted with other elements to form nitrogen.

Carbon Dioxide - Proportions decreases as plants used this gas during photosynthesis.

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How much 10.0 M HNO must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH

Naya [18.7K]

Explanation:

It is given that molarity of acetic acid = 0.0100 M

Therefore, moles of acetic acid = molarity of acetic acid × volume of buffer

Moles of acetic acid = 0.0100 M × 1.00 L

= 0.0100 mol

Similarly, moles of acetate = molarity of sodium acetat × volume of buffer

= 0.100 mol

When $HNO_{3}$ is added, it will convert acetate to acetic acid.

Hence, new moles acetic acid = (initial moles acetic acid) + (moles $HNO_{3}$ )

= 0.0100 mol + x

New moles of sodium acetate = (initial moles acetate) - (moles $HNO_{3}$ )

= 0.100 mol - x

According to Henderson - Hasselbalch equation,

pH = $pK_{a} + log\frac{[conjugate base]}{[weak acid]}$

pH = $pKa + log\frac{(new moles of sodium acetate)}{(new moles of acetic acid)}$

4.95 = 4.75 + $log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$

$log\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = 4.95 - 4.75

= 0.20

$\frac{(0.100 mol - x)}{(0.0100 mol + x)}$ = antilog (0.20)

= 1.6

Hence, x = 0.032555 mol

Therefore, moles of $HNO_{3}$ = 0.032555 mol

volume of $HNO_{3}$ = $\frac{moles HNO_{3}}{molarity of HNO_{3}}$

= $\frac{0.032555 mol}{10.0 M}$

= 0.0032555 L

or, = 3.25 (as 1 L = 1000 mL)

Thus, we can conclude that volume of $HNO_{3}$ added is 3.26 mL.

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3 years ago

1. what is volume?

gavmur [86]

1) D) The amount of space a substance takes up
2) A) The amount of matter in a substance

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4 years ago

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Answer:

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2 years ago

A shiny chunk of metal is found to have a mass of 37.28g. The metal is dropped into a graduated cylinder which contains 20.0 mL

Amanda [17]

Answer: The density of the material is 2.66 g/mL and it is likely this is made of Aluminum

Explanation:

The first step to know the material of the chunk of metal is to calculate its density. The general formula for density is P (density) = $\frac{m (mass)}{ v (volume)}$ . Moreover, in this case, it is known the mass is 37.28 g, but the volume is not directly provided. However, we know the water in the graduated cylinder had a volume of 20.0 mL and this increased to 34.0 mL when the chunk of metal is added, this means the volume of the metal is 14 mL (34.0 mL - 20.0 mL = 14 mL). Now let's calculate the density:

$P =$ $\frac{37.28g}{14.0mL}$

$P = 2.66 g/mL$

This means the density of this metal is 2.66 g/mL, which can be rounded as 2. 7 g/mL, and according to the chart, this is the density of aluminum. Therefore, this material of this chunk is aluminum.

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4 years ago

How many moles of Magnesium Oxide are in 35g?

irga5000 [103]

Answer:

0.88mol

Explanation:

The number of moles, n, contained in a substance can be calculated using the formula;

Moles (n) = mass (m) ÷ molar mass (MM)

Molar mass of Magnesium oxide (MgO) = 24 + 16

= 40g/mol

According to the question, Mass of MgO = 35grams

Mole = 35/40

Mole = 0.875

Mole = 0.88mol

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3 years ago