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Kisachek [45]
3 years ago
6

Drag the tiles to the boxes to form correct pairs.

Chemistry
2 answers:
strojnjashka [21]3 years ago
8 0

Answer:

1) Proportions decreased as it reacted with other elements to form nitrogen. -AMMONIA

2) Proportions decreased as this lighter gas was blown away by solar winds.- HYDROGEN

3) Proportions increased as this gas was released through volcanic eruptions. -WATER VAPOR

4) Proportions increased as plants released this gas into the atmosphere.- OXYGEN

5)Proportions decreased as plants used this gas during photosynthesis.- CARBON DIOXIDE

Explanation:

IT'S RIGHT 100 %

77julia77 [94]3 years ago
5 0

Answer:

Oxygen - Proportions increased as plants released this gas into the atmosphere.

Water Vapor -  Proportions decreased as this lighter gas was blown away by solar winds.

Hydrogen - Proportions increased as this gas was released through volcanic eruptions.

Ammonia - Proportions decreased as it reacted with other elements to form nitrogen.

Carbon Dioxide - Proportions decreases as plants used this gas during photosynthesis.

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Answer:

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Based on the chemical formula of the compound, that is, Al2O3, it is shown that the ions of Al3+ and O2- are kept close due to the activity of the strong electrostatic ionic bonds. The electrostatic forces and the ionic bonding between the ions are extremely robust due to the presence of the ions high charge density. Therefore, to dissociate the bonds, an enormous amount of energy is needed, and at the same time, a high amount of lattice energy is present.  

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3 years ago
Which of the following describes a use of thermal energy? * A heater warming a room A flashlight shining on a wall A football fl
katrin2010 [14]

Answer:

A heater warming a room

Explanation:

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Lori’s family is on a road trip. They split their drive into the five legs listed in the table. Find the average velocity for ea
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A compound that is composed of molybdenum (Mo) and oxygen (O) was produced in a lab by heating molybdenum over a Bunsen burner.
irakobra [83]
First, we determine the mass of each element from the data collected. We can get the mass of molybdenum Mo from the difference between the mass of crucible and molybdenum and the mass of crucible:
     Mass of molybdenum = 39.52 – 38.26 = 1.26 g Mo

We can calculate for the mass of molybdenum oxide from the difference between the mass of crucible and molybdenum oxide and the mass of crucible:
     Mass of molybdenum oxide = 39.84 – 38.26 = 1.58g 

We can now compute for the mass of oxygen O by subtracting the mass of molybdenum from the mass of molybdenum oxide:
     Mass of oxygen in molybdenum oxide = 1.58 – 1.26 = 0.32g O

To convert mass to moles, we use the molar mass of each element.
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     0.32 g O * 1 mol O / 15.999 g O = 0.0200 mol O

0.0131 mol is the smallest number of moles. We divide each mole value by this number:
     0.0131 mol Mo / 0.0131 = 1
     0.0200 mol O / 0.0131 = 1.53

Multiplying these results by 2 to get the lowest whole number ratio,
     0.0131 mol Mo / 0.0131 = 1 * 2 = 2
     0.0200 mol O / 0.0131 = 1.5 * 2 = 3
Thus, we can write the empirical formula as Mo2O3.
5 0
3 years ago
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Answer:

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Explanation:

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