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GuDViN [60]
3 years ago
13

Monica's rectangular living room is 12 ft by 15 ft. She has a square rug that covers 5/9 of the area of the floor. What is the s

ide length of the square rug? Show your work.
Mathematics
1 answer:
GarryVolchara [31]3 years ago
4 0
10 ft i think. 5/9 of 180 (which is 12 x 15) is 100 and 10 x 10 is 100
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Orthogonally diagonalize the​ matrix, giving an orthogonal matrix P and a diagonal matrix D. To save​ time, the eigenvalues are
alexgriva [62]

Answer:

P=\left(\begin{array}{ccc}-\frac{2}{3}&-\frac{2}{3}&\frac{1}{3}\\\frac{1}{\sqrt{5}}&0&\frac{2}{\sqrt{5}}\\-\frac{4}{3\sqrt{5}}&\frac{\sqrt{5}}{3}&\frac{2}{3\sqrt{5}}\end{array}\right)

Step-by-step explanation:

It is a result that a matrix A is orthogonally diagonalizable if and only if A is a symmetric matrix.  According with the data you provided the matrix should be

A=\left(\begin{array}{ccc}-9&-4&2\\ -4&-9&2\\2&2&-6\\\end{array}\right)

We know that its eigenvalues are \lambda_{1}=-14, \lambda_{2}=-5, where \lambda_{2}=-5 has multiplicity two.

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E_{\lambda_{1}=-14}=\langle(-2,-2,1)\rangle,E_{\lambda_{2}=-5}=\langle(1,0,2),(-1,1,0)\rangle..

With this in mind we can form the matrices P, D that diagonalizes the matrix A so.

P=\left(\begin{array}{ccc}-2&-2&1\\1&0&2\\-1&1&0\\\end{array}\right)

and

D=\left(\begin{array}{ccc}-14&0&0\\0&-5&0\\0&0&-5\\\end{array}\right)

Observe that the rows of P are the eigenvectors corresponding to the eigen values.

Now you only need to normalize each row of P dividing by its norm, as a row vector.

The matrix you have to obtain is the matrix shown below

3 0
3 years ago
A=4, b=2,c=-1 find value of a-b+c
777dan777 [17]

Answer:

1

Step-by-step explanation:

Substitute the value of the variable into the expression and simplify.

4-2-1=1

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3 years ago
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Answer:

Step-by-step explanation:

= 9 - 7x

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vovikov84 [41]

Answer:

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The sum of the deviations is zero.

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Step-by-step explanation:

Required

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(b) True

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(c) True

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(d) True

The mean value of a distribution is always 1 value. When more values are added to the existing values or some values are removed from the existing values, the mean value will change.

(e) False

Nominal data are not numerical or quantitative data; hence, the mean cannot be calculated.

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2 years ago
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L’ (4.5,0) J’(-4.5, -4.5) K’(-4.5,4.5) i think
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