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Nina [5.8K]
4 years ago
11

Knowing what you do about the circumstances surrounding Sara’s speech, which of the following options would NOT provide Sara’s a

rgument with validity nor remain relevant to her argument?
A.
a positive survey of senior citizens regarding their experience working with Sara
B.
a positive survey of teachers and parents regarding their experience working with Sara
C.
a positive survey of politicians regarding their experience working with Sara
D.
a positive survey of high school students regarding their experience working with Sara
Physics
2 answers:
nataly862011 [7]4 years ago
8 0
B it ijiofdksmakl;vsdmakl;vsfiamk;lfdqg
asfsvsa
nevsk [136]4 years ago
3 0
The answer should be B
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Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
4 years ago
How is the way that allows us to listen to an AM/FM Radio in our car is different from the wave that allows us to listen to mu
SVETLANKA909090 [29]

Answer:

Well AM/Fm is digitally using soundwaves for cars through signal, which we cant hear without one (radio). Concerts are in real life and use wavelegnths that we hear because it bounces off overytihing.

Explanation:

4 0
2 years ago
We are given the description of an enclosure that has fencing on 3 sides and can use 3,056 yards of fencing. We are to find the
shusha [124]

Answer:

The sum of the lengths of the sides is 2292 yards and the sum of the lengths of the triangle is 3056 yards

Explanation:

Since y represents the length of fence that is opposite (parallel) to the river and x represent the length of fence perpendicular to the river.

Therefore since we can use 3,056 yards of fencing

Side perpendicular to the river = x and,

Side opposite to the river = y = 3056 - 2x

The area of the rectangle formed (A) = Perpendicular side × Parallel side

∴ A = x(3056 - 2x) = 3056x - 2x²

A = 3056x - 2x²

To maximize the area, A' (dA/dx) = 0

∴ A' = 3056 - 4x = 0

3056 - 4x = 0

4x = 3056

x = 764 yards

y =  3056 - 2x = 3056 - 2(764) = 1528 yards.

Side perpendicular to the river = 764 yards and,

Side opposite to the river = 1528 yards

The sum of the lengths of the sides = 764 + 1528 = 2292 yard and the sum of the lengths of the triangle = 764 + 764 + 1528 = 3056 yards

5 0
3 years ago
What is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k,
WITCHER [35]

The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force. This is the significance of the fact that the gravitational constant, G, is a very small number and that Coulomb’s constant, k, is a very large number

Answer: The comparison indicates that the gravitational force is a much weaker force than the electromagnetic force.

<u>Explanation: </u>

We know that the universal formula for the estimation of gravitational force is,

                       F=G \times\left(\frac{m_{1} \times m_{2}}{r^{2}}\right)

Where,

F, Gravitational force, m_{1} \text { and } m_{2}- objects masses r- The relative distance between the two objects  

G, Gravitational Constant 6.67 \times 10^{-11} \frac{N m^{2}}{k g^{2}}

And, the electrostatic force between two scalar charges according to the Coulomb’s law is,

                  F=k \times\left(\frac{q_{1} \times q_{2}}{r^{2}}\right)

F, Electrostatic force between two charges,q_{1} \text { and } q_{2}- Two scalar charges, r - The relative distance between two scalar charges, k- Coulomb’s constant 8.987 \times 10^{9} \frac{N m^{2}}{c^{2}}

Now, on comparing the values of G and k, we can easily evaluate that eventually, the gravitational force will be lesser than the coulomb’s force.  

Besides this, we can also judge this fact through various examples such as, a balloon rubbed with a cloth, easily sticks to the wall for some time. Opposing the gravitational force of the Earth which is not the case with the normal balloon.

It drops without having the electrostatic force between the wall and the balloon.  This shows that the gravitational force draws lesser impact on objects as compared to the electrostatic force.

7 0
3 years ago
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Which is an example of a stage?
Nana76 [90]

Explanation:

wait I will give it ur answer

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