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Talja [164]
3 years ago
7

At barlow school 4/9 of the 873 students are boys at willow school 2/3 of the 630 students are girls which school has the greate

r number of boys and by how many
Mathematics
1 answer:
marishachu [46]3 years ago
7 0

Answer:

There are 178 more boys in Barlow school as compared to Willow school.

Step-by-step explanation:

We are given the following in the question:

Barlow school:

Total number of students = 873

Number of boys =

=\dfrac{4}{9}\times 873 = 388

Willow school:

Total number of students = 630

Number of girls =

=\dfrac{2}{3}\times 630 = 420

Number of boys =

Total number of students - total number of girls

=630-420 = 210

Thus, Barlow school has greater number of boys than Willow school.

Difference between the number of boys =

=388-210\\=178

Thus, there are 178 more boys in Barlow school as compared to Willow school.

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I am sorry i dont understand

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A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation
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Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 2.2, \sigma = 0.3, n = 100, s = \frac{0.3}{\sqrt{100}} = 0.03

What is the approximate probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true?

This is 1 subtracted by the pvalue of Z when X = 3.1. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{3.1 - 2.2}{0.03}

Z = 30

Z = 30 has a pvalue of 1.

1 - 1 = 0

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

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4 years ago
One leg of a right triangle has a length of 5m. The other sides have lengths that are consecutive integers. Find these lengths.
pickupchik [31]

The lengths of the other two sides of the right triangle are 12 and 13

<h3>Pythagorean theorem </h3>

From the question, we are to determine the lengths of the other sides of the triangle

From the given information,

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Thus,

If the length of the other side is x

Then,

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By the <em>Pythagorean theorem</em>, we can write that

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∴ The other leg of the right triangle is 12

Hypotenuse = x + 1 = 12 + 1 = 13

Hence, the lengths of the other two sides are 12 and 13

Learn more on Pythagorean theorem here: brainly.com/question/4584452

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