A motorboat accelerates uniformly from a velocity of 6.5m/s
to the west to a velocity of 1.5m/s to the west. if its accelerate was 2.7m/s2
to the east ,
how far did it travel during the accelration? Give your
answer in units of kilometers per hour/sec. To find the acceleration of the car
we have to
<span>
1. First determine
the suitable formula for this word problem.
Which is a. A=vf-vi/t</span>
which will be
Given are: Vi= 6.5 m/s Vf= 1.5 m/s a= 2.7 m/sec2 t=1.85s
Solution:
<span>
x = v0t + ½at2</span>
<span>x = <span>16.645375 m </span></span>
Spring potential energy:
E = 0.5 * k * x²
k spring constant
x spring compression
x = √(2 * E / k) = 0.7
Answer:
Explanation:
The explanation is given in the attached document.
Answer:
Average velocity, V = 2.5m/s
Explanation:
Given the following data
Displacement = 10m
Time = 4secs
Average velocity can be defined as the rate of change in displacement with time. Velocity is a vector quantity and as such it has both magnitude and direction.
Mathematically, average velocity is given by the equation;


Substituting into the above equation;

Average velocity, V = 2.5m/s