1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anestetic [448]
3 years ago
7

One person holds a spring scale while another pulls until the scale reads 32 N. What is the force that the person holding the

Physics
1 answer:
Mila [183]3 years ago
5 0

Answer:

32 N

Explanation:

There are many students who can not get answers step by step and on time

So there are a wats up group where you can get help step by step and well explained by the trusted experts.

You might be interested in
One day, after pulling down your window shade, you notice that sunlight is passing through a pinhole in the shade and making a s
baherus [9]

Given that,

Central maximum = 1 cm

Distance from the window shade to the wall =4 m

We know that,

The visible range of the sun light is 400 nm to 700 nm.

(a). We need to calculate the average wavelength

Using formula of average wavelength

\lambda_{avg}=\dfrac{\lambda_{1}+\lambda_{2}}{2}

Put the value into the formula

\lambda_{avg}=\dfrac{400+700}{2}

\lambda_{avg}=550\ nm

(b). We need to calculate the diameter of the pinhole

Using formula for diameter

w=\dfrac{2.44\lambda L}{D}

D=\dfrac{2.44\lambda L}{w}

Put the value into the formula

D=\dfrac{2.44\times550\times10^{-9}\times4}{1\times10^{-2}}

D=0.537\ mm

Hence, (a). The average wavelength 550 nm.

(b). The diameter of the pinhole is 0.537 mm.

7 0
3 years ago
A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at In a few mi
Nataliya [291]

Answer:

2274 J/kg ∙ K

Explanation:

The complete statement of the question is :

A lab assistant drops a 400.0-g piece of metal at 100.0°C into a 100.0-g aluminum cup containing 500.0 g of water at 15 °C. In a few minutes, she measures the final temperature of the system to be 40.0°C. What is the specific heat of the 400.0-g piece of metal, assuming that no significant heat is exchanged with the surroundings? The specific heat of this aluminum is 900.0 J/kg ∙ K and that of water is 4186 J/kg ∙ K.

m_{m} = mass of metal = 400 g

c_{m} = specific heat of metal = ?

T_{mi} = initial temperature of metal = 100 °C

m_{a} = mass of aluminum cup = 100 g

c_{a} = specific heat of aluminum cup = 900.0 J/kg ∙ K

T_{ai} = initial temperature of aluminum cup = 15 °C

m_{w} = mass of water = 500 g

c_{w} = specific heat of water = 4186 J/kg ∙ K

T_{wi} = initial temperature of water = 15 °C

T = Final equilibrium temperature = 40 °C

Using conservation of energy

heat lost by metal = heat gained by aluminum cup + heat gained by water

m_{m} c_{m} (T_{mi} - T) = m_{a} c_{a} (T - T_{ai}) + m_{w} c_{w} (T - T_{wi} ) \\(400) (100 - 40) c_{m} = (100) (900) (40- 15) + (500) (4186) (40 - 15)\\ c_{m} = 2274 Jkg^{-1}K^{-1}

7 0
3 years ago
Complete the paragraph to describe the relationship between kinetic energy and braking distance. Use . A car moves at a speed of
Mariana [72]

ke prop to v^2

ke1/v1^2=ke2/v2^2

400/50x50=joules/100x100

400x2x2

1600j

7 0
3 years ago
Read 2 more answers
When you double your speed, it takes about _____ times as much distance to stop?
Zigmanuir [339]
4 times as much distance to stop
8 0
3 years ago
I stretch a rubber band and "plunk" it to make it vibrate in its fundamental frequency. I then stretch it to twice its length an
Nikitich [7]

Answer:

The new frequency (F₂ ) will be related to the old frequency by a factor of one (1)

Explanation:

Fundamental frequency = wave velocity/2L

where;

L is the length of the stretched rubber

Wave velocity = \sqrt{\frac{T}{\frac{M}{L}}}

Frequency (F₁) = \frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}

To obtain the new frequency with respect to the old frequency, we consider the conditions stated in the question.

Given:

L₂ =2L₁ = 2L

T₂ = 2T₁ = 2T

(M/L)₂ = 0.5(M/L)₁ = 0.5(M/L)

F₂ = \frac{\sqrt{\frac{2T}{0.5(\frac{M}{L})}}}{4*L} = \frac{\sqrt{4(\frac{T}{\frac{M}{L}}})}{4*L} = \frac{2}{2} [\frac{\sqrt{\frac{T}{\frac{M}{L}}}}{2*L}] = F_1

Therefore, the new frequency (F₂ ) will be related to the old frequency by a factor of one (1).

7 0
3 years ago
Other questions:
  • Which pair of sentences is describing the same velocity? A car is parked. A car is moving in circles. A bus drives 40 miles per
    9·2 answers
  • Hail comes straight down at a mass rate of m/Δt = 0.050 kg/s and an initial velocity of v0 = -15 m/s and strikes the roof perpen
    14·1 answer
  • A roller coaster at an amusement park goes from the top of a tall hill to the bottom. during this time, the roller coaster
    6·1 answer
  • The chief by 3 3/4 kg of Apple's 7 1/4 kilograms of peers and 10 1/8 kilograms with orange about how many kilograms of fruit did
    7·2 answers
  • How many groups are in the modern periodic table?<br><br> 12<br> 18<br> 22<br> 24
    6·2 answers
  • Meeting URL: https://meet.google.com/goq-wpub-frp
    6·2 answers
  • A train whistle is heard at 350 Hz as the train approaches town. The train cuts its speed in half as it nears the station, and t
    11·1 answer
  • Look at the simple machine shown below and determine the mechanical
    9·1 answer
  • What is the difference between beat and beat frequency.
    9·2 answers
  • A 5.2 kg cat and a 2.5 kg bowl of tuna fish are at opposite ends of the 4.0-m-long seesaw. How far to the left of the pivot must
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!