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3 years ago

Help quick!!!!!

1 answer:

8 0

A/ pressure and collision frequency increase.
think of it this way. there's less room in total when u decrease volume, so particles will hit more often because they travel less

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An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinet

Leya [2.2K]

Answer:

22583.5J

Explanation:

KE=1/2 mv^2

=1/2*47Kg*(31m/s^2)

=23.5Kg * 961m/s^2

=22583.5J

7 0

2 years ago

The potential energy for a certain mass moving in one dimension is given by U(x)=(2.0J/m3)x3−(15J/m2)x2+(36J/m)x−23JU(x)=(2.0J/m

Angelina_Jolie [31]

Answer:x=2 and x=3

Explanation:

Given

Potential Energy for a certain mass is

$U(x)=2x^3-15x^2+36x-23$

and we know force is given by

$F=-\frac{\mathrm{d} U}{\mathrm{d} x}$

$F=-(2\times 3x^2-15\times 2x+36)$

For Force to be zero F=0

$\Rightarrow 6x^2-30x+36=0$

$\Rightarrow x^2-5x+6=0$

$\Rightarrow x^2-2x-3x+6=0$

$\Rightarrow (x-2)(x-3)=0$

Therefore at x=2 and x=3 Force on particle is zero.

8 0

3 years ago

What is relative velocity?

joja [24]

Search it up bruhhhhhhhhhhhhh

5 0

3 years ago

Read 2 more answers

Name the quantity which is measured by the area occupied below the velocity time graph

kiruha [24]

If you mark off a beginning time and ending time on the graph,
then the area under the part of the graph between those limits
is the distance covered during that period of time.

3 0

3 years ago

Read 2 more answers

A reconnaissance plane flies 556 km away from

9966 [12]

We use the formula, to calculate the average speed of the round trip,

$v_{av} =\frac{d_{total}}{t_{total}}$

Here, $d_{total}$ , is total distance covered by plane in total time, $t_{total}$ .

For the round trip,

$d_{total=556\ km+556\ km=1112 \times 10^3\ m$

$t_{total}=\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}$ .

Thus,

$v_{av} =\frac{1112 \times 10^3\ m}{\frac{556 \times 10^3 m}{832 m/s} + \frac{556 \times 10^3 m}{1248 m/s}} =\frac{1112 \times 10^3\ m}{668.26\ s+445.51\s} \\\\v_{av}=998.41\ m/s$ .

5 0

3 years ago