The complete sentence is:
A calorimeter directly measures changes in temperature in order to calculate specific heat.
In fact, the amount of energy acquired/released by a substance is directly proportional to its change in temperature due to the equation
![Q=mC_s \Delta T](https://tex.z-dn.net/?f=Q%3DmC_s%20%5CDelta%20T)
where Q is the amount of energy, m is the mass of the substance, Cs is the specific heat of the substance and
is the change in temperature. Therefore, by knowing Q, m and by measuring the change in temperature, it is possible to calculate Cs, the specific heat capacity of the substance.
Answer:
![D_T=18.567m](https://tex.z-dn.net/?f=D_T%3D18.567m)
Explanation:
From the question we are told that:
Acceleration ![a=8.0 m/s^2](https://tex.z-dn.net/?f=a%3D8.0%20m%2Fs%5E2)
Displacement ![d=1.05 m](https://tex.z-dn.net/?f=d%3D1.05%20m)
Initial time ![t_1=6.0s](https://tex.z-dn.net/?f=t_1%3D6.0s)
Final Time ![t_2=2.5s](https://tex.z-dn.net/?f=t_2%3D2.5s)
Generally the equation for Velocity of 1.05 travel is mathematically given by
Using Newton's Law of Motion
![V^2=2as](https://tex.z-dn.net/?f=V%5E2%3D2as)
![V=\sqrt{2*6*1.05}](https://tex.z-dn.net/?f=V%3D%5Csqrt%7B2%2A6%2A1.05%7D)
![V=4.1m/s](https://tex.z-dn.net/?f=V%3D4.1m%2Fs)
Generally the equation for Distance traveled before stop is mathematically given by
![d_2=v*t_1](https://tex.z-dn.net/?f=d_2%3Dv%2At_1)
![d_2=3.098*4](https://tex.z-dn.net/?f=d_2%3D3.098%2A4)
![d_2=12.392](https://tex.z-dn.net/?f=d_2%3D12.392)
Generally the equation for Distance to stop is mathematically given by
Since For this Final section
Final velocity ![v_3=0 m/s](https://tex.z-dn.net/?f=v_3%3D0%20m%2Fs)
Initial velocity ![u_3=4.1 m/s](https://tex.z-dn.net/?f=u_3%3D4.1%20m%2Fs)
Therefore
Using Newton's Law of Motion
![-a_3=(4.1)/(2.5)](https://tex.z-dn.net/?f=-a_3%3D%284.1%29%2F%282.5%29)
![-a_3=1.64m/s^2](https://tex.z-dn.net/?f=-a_3%3D1.64m%2Fs%5E2)
Giving
![v_3^2=u^2-2ad_3](https://tex.z-dn.net/?f=v_3%5E2%3Du%5E2-2ad_3)
Therefore
![d_3=\frac{u_3^2}{2ad_3}](https://tex.z-dn.net/?f=d_3%3D%5Cfrac%7Bu_3%5E2%7D%7B2ad_3%7D)
![d_3=\frac{4.1^2}{2*1.64}](https://tex.z-dn.net/?f=d_3%3D%5Cfrac%7B4.1%5E2%7D%7B2%2A1.64%7D)
![d_3=5.125m](https://tex.z-dn.net/?f=d_3%3D5.125m)
Generally the Total Distance Traveled is mathematically given by
![D_T=d_1+d_2+d_3](https://tex.z-dn.net/?f=D_T%3Dd_1%2Bd_2%2Bd_3)
![D_T=5.125m+12.392+1.05 m](https://tex.z-dn.net/?f=D_T%3D5.125m%2B12.392%2B1.05%20m)
![D_T=18.567m](https://tex.z-dn.net/?f=D_T%3D18.567m)
Answer:
"A blackbody is an object that absorbs all of the radiation that it receives(that is,it does not reflect any light,nor does it allow any light to pass through it and out the other side).The energy that the blackbody absorbs heats it up,and then it will emit its own radiation."
Explanation:
Risk*
To solve this problem it is necessary to apply the concepts related to the Moment. The moment in terms of the Force and the time can be expressed as
![\Delta P = F\Delta t](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%20F%5CDelta%20t)
F = Force
![\Delta t = Time](https://tex.z-dn.net/?f=%5CDelta%20t%20%3D%20Time)
At the same time the moment can be expressed in terms of mass and velocity, mathematically it can be given as
![P = m \Delta v](https://tex.z-dn.net/?f=P%20%3D%20m%20%5CDelta%20v)
Where
m = Mass
Change in velocity
Our values are given as
![\Delta t=1.65s](https://tex.z-dn.net/?f=%5CDelta%20t%3D1.65s)
By equating the two equations we can find the Force,
![F\Delta t = m\Delta v](https://tex.z-dn.net/?f=F%5CDelta%20t%20%3D%20m%5CDelta%20v)
![F = \frac{m\Delta v}{\Delta t}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7Bm%5CDelta%20v%7D%7B%5CDelta%20t%7D)
![F = \frac{62(1.1-5.5)}{1.65}](https://tex.z-dn.net/?f=F%20%3D%20%5Cfrac%7B62%281.1-5.5%29%7D%7B1.65%7D)
Therefore, the net average force will be:
![F = - 165N](https://tex.z-dn.net/?f=F%20%3D%20-%20165N)
The negative symbol indicates that the direction of the force is upwards.
<h2>
Impulse = 4.9 kgm/s</h2>
Explanation:
Impulse is given by change of momentum.
Mass of softball = 0.49 kg
Initial velocity of softball = 13 m/s
Initial momentum = 0.49 x 13 = 6.37 kgm/s
Final velocity of softball = 23 m/s
Final momentum = 0.49 x 23 = 11.27 kgm/s
Change of momentum = Final momentum - Initial momentum
Change of momentum = 11.27 - 6.37
Change of momentum = 4.9 kgm/s
Impulse = Change of momentum
Impulse = 4.9 kgm/s