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Lubov Fominskaja [6]
3 years ago
14

Consider the aquatic phosphorus cycle. On land most phosphorus is found in rocks and minerals. In the oceans, phosphorus is depo

sited from decomposition, excretion from animals, run-off from the land, and finally ______________ of rocks and minerals.
A) deposition
B) erosion
C) reformation
D) weathering

Physics
2 answers:
Paraphin [41]3 years ago
8 0

Answer: D) weathering

Phosphorus is a chemical organic element that is found in numerous compounds of the Earth typically found in water, sediments and soils. The phosphorus in the soil is being added up by the chemical fertilizers. In the ocean or marine water the phosphorus is deposited as animal waste and by the weathering of the rocks and minerals.

The weathering is a process by which the rocks are broken down into small parts and sediments by the action of the physical agents such as water, wind and chemicals. In the given situation the weathering is the process by which the element phosphorus will be added to the bottom bed of the ocean.

dmitriy555 [2]3 years ago
4 0
D) weathering  im 100% sure i took the test and i pasted so i know 
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3 0
3 years ago
Read 2 more answers
Crystal kick the 3.0 kg soccer ball horizontally off of the top of a building the building is 6.0 m tall and the ball lands 10.0
sattari [20]

Answer:

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3 0
3 years ago
A 20-cm-long, 190 g rod is pivoted at one end. A 19 g ball of clay is stuck on the other end.
MaRussiya [10]

Answer:

0.76 s

Explanation:

We are given that

Length of rod,L=20 cm=\frac{20}{100}=0.20m

1 m=100 cm

Mass of rod,M=190 g=\frac{190}{1000}=0.19kg

Mass of ball,m=19 g=\frac{19}{1000}=0.019 kg

Using 1 kg=1000g

We have to find the period if the rod and clay swing as a  pendulum.

Moment of inertia of rod-clay=Moment of inertia of rod+moment of inertia of clay

I_{rod-clay}=I_{rod}+I_{clay}

I_{rod-clay}=\frac{1}{3}ML^2+mL^2

Substitute the values then we get

I_[rod-clay}=\frac{1}{3}(0.19)(0.20)^2+(0.019)(0.20)^2

I_{rod-clay}=3.29\times 10^{-3} kgm^2

Now, the center of mass of the combination of the rod and clay is given by

y=\frac{Md_1+md_2}{M+m}

Substitute d_1=\frac{L}{2}=Distance between pivot and the center of the rod

d_2=L=The distance  between rod and clay

Using the formula

y=\frac{0.19\times \frac{0.20}{2}+0.019\times 0.20}{0.19+0.019}

y=0.1091 m

Time period of the oscillation of the system of the rod and the clay is given by

T=2\pi\sqrt{\frac{I_{rod-clay}}{(M+m)yg}}

g=9.8m/s^2

Using the formula

Time period=2\times 3.14\sqrt{\frac{3.29\times 10^{-3}}{(0.19+0.019)\times 9.8\times 0.1091}}

Time-period=0.76 s

Hence, the period =0.76 s

8 0
3 years ago
What is the weight of a basketball with a mass of 0.5 kg
IgorLugansk [536]

W = 4.9N. The weight of a basketball with a mass of 0.5Kg is 4.9N.

The weight of an object is the force of gravity on the object and can be defined as the product of the mass by the acceleration of gravity, w = mg.

W = (0.5Kg)(9.8 m/s²) = 4.9N

6 0
3 years ago
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