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Mrrafil [7]
3 years ago
14

What body systems help these cells get the energy they need?

Physics
1 answer:
MakcuM [25]3 years ago
3 0

The body systems that help cells get the energy they need are the digestive system and circulatory system. The first system is the digestive system because when you eat food, your body breaks it down using the stomach and other different parts of the digestive system.  The next one is the circulatory system because your blood carries the nutrients you acquired from food you digested to the cells throughout your body.

You might be interested in
How to find instantaneous velocity physics?
evablogger [386]
You should have the velocity as a function of time either given explicitly or implicitly (a graph)

v = ds/dt  (differentiating the position vector)

integrating the acceleration.

you can use impulse or work and energy principle and also newton law of motion to find acceleration then velocity


NOT SURE IF THAT WHAT YOU WANT.
 
8 0
3 years ago
Which of the following is a difference between electromagnetic waves and sound waves?
Paul [167]

Answer:

D

Explanation:

A is wrong as otherwise the ocean would be black as light could not pass through it to create images.

B is wrong. This is a weird one as the electromagnetic spectrum attached below shows that radio waves have the least amount of energy vs gamma which has the highest and you can't really compare this to sound waves.

C just straight up false.

D is correct, no way to remember this, just learn it. a couple of facts about transverse waves of google. Electromagnetic waves are a type of transverse waves.  These waves do not require a medium to travel.  As the name of the waves imply, these waves show electrical and magnetic properties.  No any charge occur in the waves.  Electromagnetic waves work by the laws of reflection and refraction.  They travel as straight lines in a vacuum at a speed of 3 x 10 8 ms -1.

Extra info:

As gamma waves have the highest energy it means that the waves are closer together (the wavelength is smaller) and they create more heat. Also gamma waves go through everything, X-ray only through skin and bounces of dense things like bones, which creates images. These eventually weaken more and more until radio waves do not pass through anything and just bounces around and everywhere which allows you to gain more coverage on a radio then on a cell phone.

7 0
3 years ago
after stating a hypothesis, what is thew next step that a physicist is most likwely to take in answering a question
kifflom [539]

Answer:

Planning and performing an experiment to answer the question.

Explanation:

5 0
3 years ago
Sirius A has a luminosity of 26 LSun and a surface temperature of about 9400 K.What is its radius?
wlad13 [49]

Answer

Given,

Sirius A surface temperature,T = 9400 K

Sirius A luminosity,L = 26 L₀

L₀ is the luminosity of sun.

Radius of sun =  695700000 m

Temperature on sun surface = 5780 K

Luminous intensity is given by:-

L=4 \pi R^{2} \sigma T^{4}

Now

\frac{L}{L_{0}}=\frac{4 \pi R^{2} \sigma T^{4}}{4 \pi R_{0}^{2} \sigma T_{0}^{4}}=26

\Rightarrow \frac{R^{2} T^{4}}{R_{0}^{2} T_{0}^{4}}=26

\Rightarrow R^{2}=26 \times \frac{R^{2} T_{0}^{4}}{T^{4}}=26 \times \frac{695700000^{2} \times 5780^{4}}{9400^{4}}

R=1341246640\ m=1.34 \times 10^{9}

7 0
3 years ago
The wavelength of red helium-neon laser light in air is 632.8 nm.
e-lub [12.9K]

(a) 4.74\cdot 10^14 Hz

The frequency of an electromagnetic wave is given by:

f=\frac{c}{\lambda}

where

c=3.0\cdot 10^8 m/s is the speed of the wave in a vacuum (speed of light)

\lambda is the wavelength

In this problem, we have laser light with wavelength

\lambda=632.8 nm=6.33\cdot 10^{-7} m. Substituting into the formula, we find its frequency:

f=\frac{3.0\cdot 10^8 m/s}{6.33\cdot 10^{-7} m}=4.74\cdot 10^14 Hz

(b) 427.6 nm

The wavelength of an electromagnetic wave in a medium is given by:

\lambda=\frac{\lambda_0}{n}

where

\lambda_0 is the original wavelength in a vacuum (approximately equal to that in air)

n is the index of refraction of the medium

In this problem, we have

\lambda_0=632.8 nm

n = 1.48 (index of refraction of glass)

Substituting into the formula,

\lambda=\frac{632.8 nm}{1.48}=427.6 nm

(c) 2.03\cdot 10^8 m/s

The speed of an electromagnetic wave in a medium is

v=\frac{c}{n}

where c is the speed of light in a vacuum and n is the refractive index of the medium.

Since in this problem n=1.48, we find

v=\frac{3\cdot 10^8 m/s}{1.48}=2.03\cdot 10^8 m/s

3 0
4 years ago
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