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3 years ago

1 example of each form of energy

1 answer:

defon3 years ago

4 0

Some of the forms of energy are: heat energy, mechanical energy, gravitational energy, electrical energy, sound energy, chemical energy, nuclear or atomic energy and so on. Some examples of this are:

Heat energy: the sun in our solar system. Mechanical energy: a moving car. Gravitational energy: a pen being held above a table. Electrical energy: lightning. Sound energy: musical Instruments. Chemical energy: batteries. Nuclear or atomic energy: the fusion reaction in the sun.

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3 years ago

Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s.

valina [46]

The answer is 1.99 × 10⁻¹⁰ m.

To calculate this we will use De Broglie wavelength formula:
λ = h/(m*v)
λ - the wavelength
h - Plank's constant: h = 6.626 × 10⁻³⁴ Js
v - speed
m - mass

It is given:
λ = ?
m = 9.11 × 10⁻²⁸ g
v = 3.66 × 10⁶ m/s

After replacing in the formula:
λ = h/(m*v) = 6.626 × 10⁻³⁴ /(9.11 × 10⁻²⁸ * 3.66 × 10⁶) = 1.99 × 10⁻¹⁰ m

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3 years ago

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Two forces, 80N and 100N acting at an angle of 60 degrees with each other, pull on an object. What single force would replace th

KIM [24]

We use the law of Cosines, resultant force

$F =\sqrt{(F_{1})^2 + (F_{2})^2 + 2 F_{1} F_{2} cos \theta }$

Here, $(F_{1})$ and $(F_{2})$ are forces acting at angle $\theta$ with each other.

Given $F_{1} = 80 N$ , $F_{2} = 100 N$ and $\theta = 60^0$ .

Substituting these given values in above formula we get

$F =\sqrt{(80)^2 + (100)^2 + 2 \times 80 \times 100 \ cos 60^0 } = 156. 20 \ N$ .

Thus, the resultant force is 156 N.

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4 years ago

A rock is thrown by applying a force of 2.50N while doing 6.00J of work. Over what distance was the force applied?

maksim [4K]

Answer:

$\boxed {\boxed {\sf 2.40 \ meters}}$

Explanation:

Work is the product of force and distance, so the formula is:

$W= F \times d$

The work is 6.00 Joules, but

1 Joule (J) is equal to 1 Newton meter (N*m).
Therefore, the work of 6.00 J is equal to 6.00 N*m

The force is 2.50 Newtons.

The known values are:

W= 6.00 N*m
F= 2.50 N

Substitute the values into the formula.

$6.00 \ N*m= 2.50 \ N *d$

We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.

$\frac {6.00 \ N*m}{2.50 \ N}=\frac{2.50 \ N * d}{2.50 \ N}$

$\frac {6.00 \ N*m}{2.50 \ N}=d$

The units of Newtons cancel out.

$\frac {6.00 m}{2.50 }=d$

$2.40 \ m =d$

The force was applied to the rock over a distance of 2.40 meters and choice C is correct.

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3 years ago