Question

A rock is thrown by applying a force of 2.50N while doing 6.00J of work. Over what distance was the force applied?

Answer 1

Answer:

$\boxed {\boxed {\sf 2.40 \ meters}}$

Explanation:

Work is the product of force and distance, so the formula is:

$W= F \times d$

The work is 6.00 Joules, but

• 1 Joule (J) is equal to 1 Newton meter (N*m).
• Therefore, the work of 6.00 J is equal to 6.00 N*m

The force is 2.50 Newtons.

The known values are:

• W= 6.00 N*m
• F= 2.50 N

Substitute the values into the formula.

$6.00 \ N*m= 2.50 \ N *d$

We are solving for distance, so we must isolate the variable, d. It is being multiplied by 2.50 Newtons and the inverse of multiplication is division. Divide both sides by 2.50 N.

$\frac {6.00 \ N*m}{2.50 \ N}=\frac{2.50 \ N * d}{2.50 \ N}$

$\frac {6.00 \ N*m}{2.50 \ N}=d$

The units of Newtons cancel out.

$\frac {6.00 m}{2.50 }=d$

$2.40 \ m =d$

The force was applied to the rock over a distance of 2.40 meters and choice C is correct.