Answer:
The observed wavelength on Earth from that hydrogen atom is .
Explanation:
Given that,
The actual wavelength of the hydrogen atom,
A hydrogen atom in a galaxy moving with a speed of,
We need to find the observed wavelength on Earth from that hydrogen atom. The speed of galaxy is given by :
is the observed wavelength
So, the observed wavelength on Earth from that hydrogen atom is . Hence, this is the required solution.
the complete question in the attached figure
we have that
d=0.51 mm------------------------- >0.00051 m
v = √(2ad) = √(2 * 1300m/s² * 0.00051 m) = 1.15 m/s initial velocity
a=9.8 m/s²
Then d = v² / 2a = (1.15m/s)² / (2*9.8) m/s² = 0.059 m = 59 mm
the answer is 59 mm
Answer:
Explanation:
Given
initial angular velocity is
when motor is turned of it started decelerating with angular acceleration
angle turned before coming to halt
here final angular velocity is zero
No of revolutions will be
Answer:
n=6.56×10¹⁵Hz
Explanation:
Given Data
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
To find
Revolutions per second
Solution
Let F be the force of attraction
let n be the number of revolutions per sec made by the electron around the nucleus then the centripetal force is given by
F=mω²r......................where ω=2π n
F=m4π²n²r...............eq(i)
as the values given where
Mass=9.1×10⁻³¹ kg
Radius distance=5.3×10⁻¹¹m
Electric Force=8.2×10⁻⁸N
we have to find n from eq(i)
n²=F/(m4π²r)
Answer:
B: a sand dune formed by deposition
Explanation: