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Oksana_A [137]
3 years ago
8

In being served, a tennis ball is accelerated from rest to a speed of 31.6 m/s. The average power generated during the serve is

2920 W. Assuming that the acceleration of the ball is constant during the serve, find the force acting on the ball.
Physics
1 answer:
joja [24]3 years ago
7 0

Answer:

The force acting on the ball is 92.4 N.

Explanation:

Given that,

Initial speed of the ball, u = 0

Final speed of the ball, v = 31.6 m/s

The average power generated during the serve is 2920 W. Power generated by an object is given by :

P=\dfrac{W}{t}

W is the work done, W = Fd

P=\dfrac{Fd}{t}

Since, v=\dfrac{d}{t}

So,

P=F\times v

F is the force acting on the ball

F=\dfrac{P}{v}\\\\F=\dfrac{2920\ W}{31.6\ m/s}\\\\F = 92.4\ N

So, the force acting on the ball is 92.4 N. Hence, this is the required solution.

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The student places 0.5 kg of potato into a pan of water.
nasty-shy [4]

Answer:

136000 J or 136 kJ

Explanation:

Formula

Heat = m * c * deltaH

Givens

m= 0.5 kg

c = 3400 J / (kg * oC)

Deltat = (100oC - 20oC)

deltat = 80oC

Solution

Heat = 0.5 kg * 3400 J/(kg* oC) * 80oC

Heat = 136000 Joules

Heat = 136 kg

Technically there is only 1 place of accuracy.

6 0
3 years ago
A waiter is carrying a tray above his head and walking at a constant velocity. If he applies a force of 5.0 newtons on the tray
Darya [45]
In physical terms, a force does work if it moves an object in the direction the force is pointing towards.

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The is no force done by this force.
3 0
4 years ago
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Do blood cells have a rigid cell wall
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5 0
3 years ago
Two parallel, circular conducting plates 32 cm in diameter are separated by 0.5 cm and have charges of +24 nC and -24 nC, respec
inysia [295]

Answer: E = 33762.39 N/c

Explanation: we calculate the capacitance of the two conducting plates ( this is because, 2 circular disc carrying opposite charges and the same dimension form a capacitor).

C = A/4πkd

Where C = capacitance of capacitor

A = Area of plates = πr² ( where r is radius which is half of the diameter)

K = electric constant = 9×10^9

d = distance between plates = 0.5cm = 0.005 m

Let us get the area, A = πr², where r = D/2 where D = diameter

r = 32/2 = 16cm = 0.16m

A = 22/7 × (0.16)² = 0.0804 m²

By substituting this into the capacitance formula, we have that

C = 0.0804/4×3.142*9×10^9 × 0.005

C = 0.0804/565486677.646

C = 142.17*10^(-12) F.

But C =Q/V where V = Ed

Hence we have that

C = Q/Ed

Where C = capacitance of capacitor = 142.17*10^(-12)F

Q = magnitude of charge on the capacitor = 24×10^-9c

E = strength of electric field =?

d = distance between plates = 0.005m

142.17*10^(-12) = 24 ×10^-9 / E × 0.005

By cross multiplying

142.17*10^(-12) × E × 0.005 = 24 ×10^-9

E = 24 ×10^-9 / 142.17*10^(-12) × 0.005

E = 33762.39 N/c

8 0
3 years ago
HELP ASAPPP PLZZZ I WILL GIVE YOU 50 POINTS
TiliK225 [7]

Answer:

c

Explanation:

c

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