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WINSTONCH [101]
3 years ago
10

A sinusoidal wave is traveling along a rope. The oscillator that generates the wave completes 43.0 vibrations in 29.0 s. A given

crest of the wave travels 430 cm along the rope in 14.0 s. What is the wavelength of the wave?
Physics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

wavelength is 20.71 cm

Explanation:

given data

wave = 43.0 vibrations

time = 29 s

wave travels = 430 cm

time t2 = 14 s

to find out

wavelength

solution

we know here wavelength formula that is

wavelength = velocity / frequency  .........................1

here frequency = 43 / 29 = 1.4827 Hz

and velocity = 430 / 14 = 30.71 cm/s

so here from equation 1 put all value

wavelength = velocity / frequency

wavelength = 30.71 / 1.4827

wavelength = 20.71 cm

so wavelength is 20.71 cm

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A baseball pitcher loosens up his pitching arm. He tosses a 0.20-kg ball using only the rotation of his forearm, 0.28 m in lengt
aev [14]

Answer:

Moment of Inertia, I = 0.016 kgm²

Explanation:

Mass of the ball, m = 0.20 kg

Length of the pitcher's arm, l = 0.28

Radius of the circular arc, r = 0.28 m

Moment of Inertia is given by the formula:

I = mr²

I = 0.20 * 0.28²

I = 0.20 * 0.0784

I = 0.01568

I = 0.016 kgm²

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Noble gases, such as argon and neon, are known for being extremely non-reactive. Neon and argon are non-reactive because they A.
Greeley [361]
B. have eight electrons in their outer shell
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Describe the energy transformations that occur in a waterfall...
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<span>At the top of the waterfall, the water has potential energy. Once it goes over</span>
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3 years ago
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HELP PLEASE 20 POINTS SHOW WORK, ALL EQUATIONS
nataly862011 [7]

Answer:

s = 3 m

Explanation:

Let t be the time the accelerating car starts.

Let's assume the vehicles are point masses so that "passing" takes no time.

the position of the constant velocity and accelerating vehicles are

s = vt = 40(t + 2)  cm

s = ½at² = ½(20)(t)² cm

they pass when their distance is the same

½(20)(t)² = 40(t + 2)

10t² = 40t + 80

0 = 10t² - 40t - 80

0 = t² - 4t - 8

t = (4±√(4² - 4(1)(-8))) / 2(1)

t = (4± 6.928) / 2  ignore the negative time as it has not occurred yet.

t = 5.464 s

s = 40(5.464 + 2) = 298.564 cm

300 cm when rounded to the single significant digit of the question numerals.

7 0
3 years ago
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pu
dalvyx [7]

Answer:

The frictional torque is \tau  = 0.2505 \ N \cdot m

Explanation:

From the question we are told that

   The mass attached to one end the string is m_1 =  0.341 \ kg

   The mass attached to the other end of the string is  m_2 =  0.625 \ kg

    The radius of the disk is  r = 9.00 \ cm  = 0.09 \ m

At equilibrium the tension on the string due to the first mass is mathematically represented as

      T_1 =  m_1 *  g

substituting values

      T_1 =  0.341 * 9.8

      T_1 =  3.342 \ N

At equilibrium the tension on the string due to the  mass is mathematically represented as

      T_2 =  m_2 *  g

     T_2 = 0.625 * 9.8

      T_2 = 6.125 \ N

The  frictional torque that must be exerted is mathematically represented as

      \tau  =  (T_2 * r ) - (T_1 * r )

substituting values  

     \tau  =  ( 6.125 * 0.09 ) - (3.342  * 0.09 )

     \tau  = 0.2505 \ N \cdot m

5 0
3 years ago
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