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WINSTONCH [101]
3 years ago
10

A sinusoidal wave is traveling along a rope. The oscillator that generates the wave completes 43.0 vibrations in 29.0 s. A given

crest of the wave travels 430 cm along the rope in 14.0 s. What is the wavelength of the wave?
Physics
1 answer:
Aliun [14]3 years ago
8 0

Answer:

wavelength is 20.71 cm

Explanation:

given data

wave = 43.0 vibrations

time = 29 s

wave travels = 430 cm

time t2 = 14 s

to find out

wavelength

solution

we know here wavelength formula that is

wavelength = velocity / frequency  .........................1

here frequency = 43 / 29 = 1.4827 Hz

and velocity = 430 / 14 = 30.71 cm/s

so here from equation 1 put all value

wavelength = velocity / frequency

wavelength = 30.71 / 1.4827

wavelength = 20.71 cm

so wavelength is 20.71 cm

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The 64.5-kg climber in is supported in the “chimney” by the friction forces exerted on his shoes and back. The static coefficien
kobusy [5.1K]

Answer:

The minimum force the climber must exert is about 439N.

Explanation:

We use the relationship between friction and normal force to answer this question:

F_{friction} = \mu_{static} \cdot F_{normal}\implies F_{normal}=\frac{F_{friction}}{\mu_{static}}

We are given the static coefficients of friction but need to determine the friction force. To do that we consider the totality of forces acting on this hapless gentleman stuck in a chimney. There is the gravity acting downward (+), then there are two friction forces acting upward (-), namely through his shoes and his back. The horizontal force exerted by the climber on both walls of the chimney is the same and is met with equally opposing normal force. Since the climber is not falling the net force in the vertical direction is zero:

F_{net} = 0 = F_g - F_{shoes}-F_{back}= mg - \mu_{shoes}F_{norm}-\mu_{back}F_{norm}\\F_{norm}=\frac{mg}{\mu_{shoes}+\mu_{back}}=\frac{64.5kg\cdot 9.8\frac{m}{s^2}}{0.8+0.64}\approx 438.96N\\

The normal force in this equilibrium is about 439N and  because we are told that the static friction forces are both at their maximum, this value is at the same time the <em>minimum</em> force needed for the climber to avoid starting slipping down the chimney.



7 0
2 years ago
List and describe two ways currents affect life on earth
Karo-lina-s [1.5K]
1 A current pushes waste around in the ocean

that is all i know

6 0
3 years ago
Rahim is watching his favorite football team on television. In order to work, the television must be plugged into an electrical
Rasek [7]
I think the answer is B
8 0
3 years ago
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A 4.60 gg coin is placed 19.0 cmcm from the center of a turntable. The coin has static and kinetic coefficients of friction with
Komok [63]

Answer:

62.64 RPM.

Explanation:

Given that

m= 4.6 g

r= 19 cm

μs = 0.820

μk = 0.440.

The angular speed of the turntable = ω rad/s

Condition just before the slipping starts

The maximum value of the static friction force =Centripetal force

\mu_s\ m g=m\ \omega^2\ r\\ \omega^2=\dfrac{\mu_s\ m g}{m r}\\ \omega=\sqrt{\dfrac{\mu_s\  g}{ r}}\\ \omega=\sqrt{\dfrac{0.82\times 10}{ 0.19}}\ rad/s\\\omega= 6.56\ rad/s

\omega=\dfrac{2\pi N}{60}\\N=\dfrac{60\times \omega}{2\pi }\\N=\dfrac{60\times 6.56}{2\pi }\ RPM\\N=62.64\ RPM

Therefore the speed in RPM will be 62.64 RPM.

5 0
2 years ago
A helicopter is ascending vertically with a speed of 5.10m/s. At a height of 105m above the Earth, a package is dropped from a w
Luden [163]

Here it is given that initial speed of the package will be same as speed of the helicopter

v_i = 5.10 m/s

displacement of the package as it is dropped on ground

d = -105 m

acceleration is due to gravity

a = -9.8 m/s^2

now by kinematics

y = v* t + \frac{1}{2}at^2

-105 = 5.1 * t - \frac{1}{2}*9.8*t^2

4.9 t^2 - 5.1 t - 105 = 0

by solving above equation we have

t = 5.2 s

so it will take 5.2 s to reach the ground

7 0
3 years ago
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