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Varvara68 [4.7K]

3 years ago

5

Why is it that silver heats quicker than aluminum?

1 answer:

Sedbober [7]3 years ago

3 0

Silver is less dence than aluminum.

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Eric is creating a timeline of the formation of the solar system. Which sequence best describes the formation of the solar syste

vlada-n [284]

The answer is C. nebular are star nurseries. When the massive gas being collapsing in its own weight. Local areas of gas begin to coalesce under gravity. Due to enormous pressure, nuclear fusion begins and a protostar is formed. The protostar grows into the sun as more hydrogen fuses at the core. The planetesimal materials at the edges of the protostellar discs coalesce to form planets that orbit the star.

3 0

2 years ago

Read 2 more answers

A net force of 125 N accelerates a 25.0 kg mass. What is the resulting acceleration?

Neko [114]

Answer: $a=5 m/s^2$

Explanation:

The acceleration of an object can be calculated by using Newton's second law:

$F=ma$

where

F is the net force applied on the object

m is the mass of the object

a is its acceleration

In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:

$a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2$

5 0

3 years ago

Read 2 more answers

Sheila uses a 45N force on her bowling ball across a 15m lane. What work did she do on the bowling ball? Show your work.

Maurinko [17]

Answer:

675J

Explanation:

Given parameters:

Force = 45N

Distance = 15m

Unknown:

Work done by Sheila = ?

Solution:

Work done by a body is the amount of force applied to make a body move through a distance;

Work done = Force x distance

Now;

Work done = 45 x 15 = 675J

6 0

2 years ago

An incident ray of light strikes water at an angle of 30°. The index of refraction of air is 1.0003, and the index of refraction

defon

Answer: It’s A

Explanation:

22 degrees

6 0

3 years ago

Read 2 more answers

A 0.500-kg block, starting at rest, slides down a 30.0° incline with static and kinetic friction coefficients of 0.350 and 0.250

Leviafan [203]

Answer:x=23.4 cm

Explanation:

Given

mass of block $m=0.5 kg$

inclination $\theta =30$

coefficient of static friction $\mu =0.35$

coefficient of kinetic friction $\mu _k=0.25$

distance traveled $d=77.3 cm$

spring constant $k=35 N/m$

work done by gravity+work done by friction=Energy stored in Spring

$mg\sin \theta d-\mu _kmg\cos \theta d=\frac{kx^2}{2}$

$mgd\left ( \sin \theta -\mu _k\cos \theta \right )=\frac{kx^2}{2}$

$0.5\times 9.8\times 0.773\left ( \sin 30-0.25\cos 30\right )=\frac{35\times x^2}{2}$

$x=\sqrt{\frac{2\times 0.5\times 9.8\times 0.773(\sin 30-0.25\times \cos 30)}{35}}$

$x=0.234 m$

$x=23.4 cm$

6 0

3 years ago