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Sedaia [141]
3 years ago
13

Which points lie on the line that passes through point P and

Mathematics
2 answers:
4vir4ik [10]3 years ago
6 0

Answer:

(-5,-1)

Step-by-step explanation:

First, draw a parallel line to the blue one that has a slope of over 1 to the right and up 1.

Second, look at the new line and see if any of the points are on the line.

All of the other point do not fall on the new line.

Yuliya22 [10]3 years ago
4 0

Answer:

Option 2nd , 3rd and 5th are correct.

Step-by-step explanation:

Given:

Given line passes through points ( -2 , -4 ) and ( 4 , 2 )

Coordinate of the Point P( 0 , 4 )

To find: Point which lie on the line parallel to given line and passes through point P.

Slope of the given line = \frac{y_2-y_1}{x_2-x_1}\:=\:\frac{-4-2}{-2-4}\:=\:\frac{-6}{-6}\:=\:1

We know that slope of parallel lines ara equal.

So, Using Slope-Point form we get equation of line,

y-y_1=m(x-x_1)

y - 4 = 1 ( x - 0 )

y - 4 = x

x - y = -4

Option 1:

x = -4 , y = 2

LHS = -4 - 2 = -6 ≠ RHS

Thus, This is not required point.

Option 2:

x = -1 , y = 3

LHS = -1 - 3 = -4 = RHS

Thus, This is required point.

Option 3:

x = -2 , y = 2

LHS = -2 - 2 = -4 = RHS

Thus, This is required point.

Option 4:

x = 4 , y = 2

LHS = 4 - 2 = 2 ≠ RHS

Thus, This is not required point.

Option 5:

x = -5 , y = -1

LHS = -5 - (-1) = -4 = RHS

Thus, This is required point.

Therefore, Option 2nd , 3rd and 5th are correct.

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Answer:

a)This solution matches with the original equation and its solution

b)This solution matches with the original equation and its solution

c)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d)This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

Step-by-step explanation:

i) Which scenarios can be solved by 1.5x +  2.25 = 12.75. Select all that apply and note the given solution.

therefore 1.5x = 10.5   therefore x  = 7

a) let the number be x

   therefore if \frac{3}{2} x + \frac{9}{4}  = \frac{51}{4}  \Rightarrow  1.5x + 2.25 = 12.75  then the number x = 7.

 This solution matches with the original equation and its solution

b.) If a taxi driver charges a flat fee of $2.25 and $1.5 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 7.

This solution matches with the original equation and its solution

c)if nine quarters of a number, say x, increased by three halves is fifty one

   quarters, the number is x = 5,

   \frac{9}{4} x + \frac{3}{2}  = \frac{51}{4}  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

d.)   If a taxi driver charges a flat fee of $1.5 and $2.25 per mile, where the

     number of mile = x, then the number of miles Juan can ride the taxi for

     $12.75 is x = 5.

2.25x + 1.5  = 12.75  \Rightarrow  9x = 51 - 6 = 45 \therefore x = 5

This solution <em><u>does not</u></em> match with the original equation and its solution. Though the solution is correct the original given equation cannot be used.

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4 years ago
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Answer:

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Step-by-step explanation:

5 0
3 years ago
Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form.
algol13
Answers:
x = 24
y = 8√3
Explanation:

1) Since, the given triangle is a right triangle, and you have both an angle and the hypotenuse length, you can use some trigonometric ratios to find the variables.

2) The variables given represent:

x: adjacent-leg to angle 30°
y: opposite length to angle 30°

3) sine ratio:

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⇒ y = 16√3 sin 30° = 16√3 × (1/2) = 8√3

4) cosine ratio

cos 30° = adjacent-leg / hypotenuse = x / (16√3)

⇒ x = 16√3 cos 30° = 16√3 (√3 / 2) = 16 × 3 / 2 = 24

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