Answer:
f(x) = 1/x
Step-by-step explanation:
The corrected question is:
Suppose f is the function that satisfies
f'(x)= - f²(x)
for all x in its domain, and
f(1) = 1
f(x)= ?
Given:
f'(x) = -(f(x))²
This can be written as:
df/dx = -f²
The equation becomes:
-df/f² = dx
Integrating the above equation on both sides we get:
1/f = x + c where c is constant
So
f(x) = 1/(x+c)
Now given that:
f(1) = 1
Solving this for c we get:
f(1) = 1 = 1/(1 + c)
1 = 1/ 1+c
1 = 1 + c
c = 1 - 1
c = 0
Now put this value of c in f(x) = 1/(x+c)
f(x) = 1/(x+0)
f(x) = 1/(x)
f(x) = 1/x
Hence
f(x) = 1/x