Answer:
maybe the 3rd stance if your not sure try to search in googel
Balanced chemical reaction: 2CH₄(g) ⇄ C₂H₂(g) + 3H₂(g).
1) In a chemical reaction, chemical equilibrium is the state in which both reactants (methane CH₄) and products (ethyne C₂H₂ and hydrogen H₂) are present in concentrations which have no further tendency to change with time.
2) At equilibrium, both the forward and reverse reactions are still occurring.
3) Reaction rates of the forward and backward reactions are equal and there are no changes in the concentrations of the reactants and products.
Consider the Chemical Reaction first:
Reaction: H₂SO₄ + 2 NaCl → 2 HCl + Na₂SO₄
Now, Given mass of NaCl = 30 g
Molar mass of Nacl = 58 g/mol
Now, Number of moles of NaCl = 30/58 = 0.517 mol
Balance the equation, For every 2 molecules of NaCl, 2 molecules of HCl formed, so the number of moles would be same.
Hence, Number of moles of HCl = 0.517 mol
Now, Mass of HCl = Molar mass of HCl * Number of moles
Mass = 36 * 0.517 [ Molar mass of HCl = 36 ]
Mass = 18.62 g
In short, Your Answer would be: 18.62 Grams
Hope this helps!
Excess reactant : Na
NaCl produced : = 16.497 g
<h3>Further explanation</h3>
Given
Reaction(balanced)
2Na + Cl₂⇒ 2NaCl
20 g Na
10 g Cl₂
Required
Excess reactant
NaCl produced
Solution
mol Na(Ar = 23 g/mol) :
= 20 : 23 = 0.87
mol Cl₂(MW=71 g/mol):
= 10 : 71 g/mol = 0.141
mol : coefficient :
Na = 0.87 : 2 = 0.435
Cl₂ = 0.141 : 1 = 0.141
Limiting reactant : Cl₂(smaller ratio)
Excess reactant : Na
Mol NaCl based on mol Cl₂, so mol NaCl :
= 2/1 x mol Cl₂
= 2/1 x 0.141
= 0.282
Mass NaCl :
= 0.282 x 58.5 g/mol
= 16.497 g
Answer:
Ionic
Explanation:
Lithium is an alkali metal and form an ionic bond by donating an electron.
Fluorine is a halogen and forms ionic bonds by accepting an electron.
The electronegativity difference between lithium (0.98) and fluorine (3.98) is 3 Pauling units. Usually, when elements have a difference of 1.7 (or 2.0) Pauling units the bond is classified as ionic.
Hope this helps! If you have any more questions or need more explanation please leave a comment down below and I will reply ASAP. Good luck!
