The new volume of the hot air balloon is 801.9L.
As the temperature of the hot air balloon on the table is increased, the its volume also increases.
<h3>Charle's law</h3>
Charle's law states that the volume of an ideal gas is directly proportional to the absolute temperature provided pressure is kept at constant.
It is expressed as;
V₁/T₁ = V₂/T₂
Given the data in the question;
- Initial temperature T₁ = 26.7°C = 299.85K
- Final temperature T₂ = 48.3°C = 321.45K
To calculate the new volume we subtsitute our given values into the expression above.
V₁T₂ = V₂T₁
V₂ = V₁T₂ / T₁
V₂ = ( 748L × 321.45K ) / 299.85K
V₂ = 240444.6LK / 299.85K
V₂ = 801.9L
The new volume of the hot air balloon is 801.9L.
As the temperature of the hot air balloon on the table is increased, the its volume also increases.
Learn more about Charle's law here: brainly.com/question/21184611
Answer: 24.1 L of 2.27 M HF will react with 3.70 kg of
Explanation:
The balanced chemical reaction :
To calculate the number of moles, we use the equation:
According to stoichiometry :
1 mole of require = 4 moles of
Thus 13.7 moles of will require= of
To calculate the volume for given molarity, we use the equation:
.....(1)
Molarity of solution = 2.27 M
Volume of solution in L= ?
Putting values in equation 1, we get:
Thus 24.1 L of 2.27 M HF will react with 3.70 kg of
KE = (1/2)mv^2
m = 10.0 kg
v = 5.00 m/a
KE = (1/2)(10.0)(5.00)^2 = (1/2)(10.0)(25.0) = 125 J
C. 125 J
The answer to the question is letter D