electromagnetic spectrum is consisting of many frequency range which is from gamma rays to radio waves
they are of various wavelength and different energy levels
minimum wavelength will occurs at Gamma rays
and maximum wavelength at Radio waves
the list of increasing order of wavelength is as following
Gamma rays < X rays < Ultraviolet < Visible Light < Infrared Waves < Radio Waves
so least to maximum order is
1. Gamma rays
2. X rays
3 Ultraviolet
4 Visible light
5 Infrared waves
6 Radio waves
Hi there!
A neutral metal sphere is comprised of both ELECTRONS and PROTONS.
Recall that electrons have a NEGATIVE (-) charge, and protons have a POSITIVE (+) charge.
Opposite charges attract, and like charges repel.
In this instance, the positively-charged rod will cause the electrons in the neutral metal sphere to move towards the side facing the rod (opposite charges attract), which causes the two to be attracted to one another.
Machines are never 100% efficient because they are made by humans and we make errors and nothing we make is perfect, that's why the machines we build are not 100% accurate or efficient.
<span>c. contains different kind of matter</span>
Answer:
Circuit one will have more current than circuit two
Explanation:
I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -
V = IR,
where V = voltage / potential difference, I = current, and R = resistance
If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -
2V = I( 1 / 2R ),
4V = IR,
I = 4V / R
Whereas in the second circuit -
V = IR,
I = V / R
As you can note, voltage is directly proportional to the current ( I ) as well as the resistance. The only difference between the two formulas I = 4V / R, and I = V / R is the difference in the voltage. With the voltage being 4 times greater in the first circuit, and current is 4 times greater in the first circuit as well.
<u><em>Hence, circuit one will have more current than circuit two</em></u>
