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Aneli [31]
3 years ago
12

A binary star system consists of two stars of masses m1 and m2. The stars, which gravitationally attract each other, revolve aro

und the center of mass of the system. The star with mass m1 has a centripetal acceleration of magnitude a1. Note that you do not need to understand universal gravitation to solve this problem.Find a2, the magnitude of the centripetal acceleration of the star with mass m2.
Physics
1 answer:
zubka84 [21]3 years ago
8 0

Answer:

 a₂ = m₁ / m₂ a₁

Explanation:

For this exercise we note that the attraction between the two stars is an action and reaction force, therefore it has the same magnitude, but it is applied to each of the bodies

Let's apply Newton's second law on the star 1

     F₁ = m₁ a₁

Newton's second law in star 2

       F₂ = m₂ a₂

       | F₁ | = | F₂ |

      m₁  a₁ = m₂  a₂

      a₂ = m₁ / m₂ a₁

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Answer:

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Explanation:

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2 years ago
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The top of the pool table is 0.810 m from the floor. the placement of the tape is such that 0 m is aligned with the edge of the
8090 [49]
Compute first for the vertical motion, the formula is:

y = gt²/2 

0.810 m = (9.81 m/s²)(t)²/2 

t = 0.4064 s 


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x = (vx)t 

4.65 m = (vx)(0.4064 s) 

4.65 m/ 0.4064s = (vx)

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(vy) = (9.81 m/s²)(0.4064 s) 

(vy) = 3.99 m/s 


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v = sqrt[(11.44 m/s)² + (3.99 m/s)²] 

v = 12.12 m / s
6 0
3 years ago
Problem 2.26 MasteringPhysics 10 of 16 Problem 2.26 When striking, the pike, a predatory fish, can accelerate from rest to a spe
cluponka [151]

final velocity = initial velocity + (acceleration x time) <span>
3.9 m/s = 0 m/s + (acceleration x 0.11 s) 
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distance = (initial velocity x time) + 1/2(acceleration)(time^2) 
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6 0
3 years ago
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A laser beam is incident on two slits with a separation of 0.195 mm, and a screen is placed 5.30 m from the slits. If the bright
kumpel [21]

Answer:

λ = 596 nm.

Explanation:

Fringe width = λ D / d

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8 0
3 years ago
Use appropriate units and significant figures.  USE THE LAW OF COSINES AND LAW OF SINES.
N76 [4]

Answer:

The resultant velocity is 86.1 mi/h.    

Explanation:

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c^{2} = a^{2} + b^{2} - 2abcos(\theta)

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c: is the resultant velocity =?

a: is the velocity of the plane = 75.0 mi/h

b: is the velocity of the wind = 15.0 mi/h  

θ: is the angle between "a" and "b"                          

The angle between "a" and "b" can be found as follows:

\theta = 180.0 - 46.0 = 134.0 ^{\circ}

Now, by using the law of cosines we have:

c^{2} = (75.0)^{2} + (15.0)^{2} - 2*75.0*15.0*cos(134.0) = 7413.0

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Therefore, the resultant velocity is 86.1 mi/h.    

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Where:

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So, if we want to find "c" by using the law of sines, we need to know another angle besides θ (γ or α), and the statement does not give us.

I hope it helps you!        

3 0
3 years ago
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