Answer:
Probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Step-by-step explanation:
We are given that a veterinary researcher takes a random sample of 60 horses presenting with colic. The average age of the random sample of horses with colic is 12 years. The average age of all horses seen at the veterinary clinic was determined to be 10 years. The researcher also determined that the standard deviation of all horses coming to the veterinary clinic is 8 years.
So, firstly according to Central limit theorem the z score probability distribution for sample means is given by;
Z =
~ N(0,1)
where,
= average age of the random sample of horses with colic = 12 yrs
= average age of all horses seen at the veterinary clinic = 10 yrs
= standard deviation of all horses coming to the veterinary clinic = 8 yrs
n = sample of horses = 60
So, probability that a sample mean is 12 or larger for a sample from the horse population is given by = P(
12)
P(
12) = P(
) = P(Z
1.94) = 1 - P(Z < 1.94)
= 1 - 0.97381 = 0.0262
Therefore, probability that a sample mean is 12 or larger for a sample from the horse population is 0.0262.
Answer:
A. The data are continuous because the data can take on any value in an interval.
Step-by-step explanation:
The data surveyed is the exact mass, in grams, of food eaten by each person each day.
This type of data is continous, not discrete. The mass can take any value within the domain of positive real numbers. It represents a physic variable, and they are always continous.
It’s rational because the square root of 0.49 is 0.7
Answer:

Step-by-step explanation:

Find the GCD of
:





So the prime factor common to 6, 8 is:

So the factor common to
:
