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nata0808 [166]
3 years ago
10

Find the greatest common factor of 18, 36,18,

Mathematics
1 answer:
Vikki [24]3 years ago
5 0

Answer:

Step-by-step explanation:

18=2(3)3

36=2(2)3(3)

The GCF will be the product of their common factors, specifically 2(3)3=18

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Can someone please help me?
Katyanochek1 [597]
The matrix represents the system:

-3x+5y=15

2x+3y=-10, which is choice c. 


We can see it more clearly from the way we multiply matrices, as follows:

\[
  \left[ {\begin{array}{cc}
   -3 & 5 \\
    \ 2  & 3 \\
  \end{array} } \right]
\] \cdot  \[
  \left[ {\begin{array}{c}
   x \\
    y \\
  \end{array} } \right]
\]= \left[ {\begin{array}{c}
   -3\cdot x+5\cdot y \\
    2\cdot x+3\cdot y \\
  \end{array} } \right]
\]= \[ \left[ {\begin{array}{c} 15 \\ -10 \\ \end{array} } \right] \]

Answer: C
7 0
4 years ago
What are two equivalent ratios for 8/9
Georgia [21]
(16/18)
(24/27)

You just times 8 and 9 by the same number, like:
(8•2/9•2)=(16/18)
(8•3/9•3)=(24/27)

You could do any number:
(8•100/9•100)=(800/900)

8 0
4 years ago
What are the coordinators of the vertex of the graph of the function -2(x-1)^2 = y+5
mamaluj [8]
The answer is, (1, -5)... 
7 0
3 years ago
Diego wants to have $1,000,000 in 5 years. He plans to invest $250,000 to start and make yearly payments of $125,000 to the acco
julia-pushkina [17]

Answer:

Yes

Step-by-step explanation:

With the $875,000 from his input alone he is really close to $1,000,000 and doing simple intrest on the $250,000 is $105,000 a year is he earns 3.5% intrest a month.

So in 5 years he'll have about $1,662,500 using simple intrest but with compound it'd be more like 2mil

Hope this helps!

5 0
2 years ago
On a coordinate plane, triangle A B C is shown. Point A is at (0, 0), point B is at (3, 4), and point C is at (3, 2). What is th
Elena L [17]

Answer:

The area of triangle for the given coordinates is  1.5\sqrt{4.6}

Step-by-step explanation:

Given coordinates of triangles as

A = (0,0)

B = (3,4)

C = (3,2)

So, The measure of length AB = a = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, a = \sqrt{(3-0)^{2}+(4-0)^{2}}

Or, a =  \sqrt{9+16}

Or, a =   \sqrt{25}

∴ a = 5 unit

Similarly

The measure of length BC = b = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, b = \sqrt{(3-3)^{2}+(2-4)^{2}}

Or, a =  \sqrt{0+4}

Or, b =   \sqrt{4}

∴ b = 2 unit

And

So, The measure of length CA = c = \sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

Or, c = \sqrt{(3-0)^{2}+(2-0)^{2}}

Or, c =  \sqrt{9+4}

Or, c =   \sqrt{13}

∴ c = \sqrt{13} unit

Now, area of Triangle written as , from Heron's formula

A = \sqrt{s\times (s-a)\times (s-b)\times (s-c)}

and s = \frac{a+b+c}{2}

I.e  s = \frac{5+2+\sqrt{13}}{2}

Or. s =  \frac{7+\sqrt{13}}{2}

So, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times ((\frac{(7+\sqrt{13})}{2})-5)\times (\frac{7+\sqrt{13}}{2}-2)\times (\frac{7+\sqrt{13}}{2}-\sqrt{13})}

Or, A = \sqrt{(\frac{(7+\sqrt{13})}{2})\times (\frac{(\sqrt{13}-3)}{2})\times (\frac{4+\sqrt{13}}{2})\times (\frac{7-\sqrt{13}}{2})}

Or, A = \frac{3}{2} × \sqrt{1+\sqrt{13} }

∴  Area of triangle = 1.5\sqrt{4.6}

Hence The area of triangle for the given coordinates is  1.5\sqrt{4.6}  Answer

7 0
3 years ago
Read 2 more answers
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