Mass of Nd₂(SO₄)₃ : 2.653 g
<h3>Further explanation</h3>
Reaction
Nd₂Fe₁₄B + 17H₂SO₄ → Nd₂(SO₄)₃ + 14FeSO₄ + B + 17H₂
5 g Nd₂Fe₁₄B
MW = 2. 144,242 + 14. 55.845 + 10.811
MW = 288.484 + 781.83+10.811=1081.125 g/mol
mol :

mol Nd₂Fe₁₄B = mol Nd₂(SO₄)₃=0.0046
so mass of Nd₂(SO₄)₃ :
MW Nd₂(SO₄)₃ = 2.144.242+3.32,065+12.15,999
MW = 288.484+96.195+191.988=576.667 g/mol

A fluorine atom has seven valence electrons. ... Carbon will then have five valence electrons (its four and the one its sharing with fluorine). Covalently sharing two electrons is also known as a “single bond.” Carbon will have to form four single bonds with four different fluorine atoms to fill its octet.