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Serga [27]
3 years ago
12

Classify each of the following substances as either a strong or weak acid, strong or weak base, or a soluble or insoluble salt.

Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

KOH is a strong base, HClO_{4} is a strong acid, HNO_{2} is a weak acid, NaBr is a soluble salt and PbCl_{2} is an insoluble salt

Explanation:

According to solubility rule, all chlorides, bromides and iodides of metal ions are soluble except for Pb^{2+},Ag^{+} and Hg^{+}[/tex].

Therefore NaBr is a soluble salt and PbCl_{2} is an insoluble salt.

There are seven strong acids : HCl, HBr, HI, H_{2}SO_{4}, HNO_{3}, HClO_{3} and HClO_{4}.

All group IA metal hydroxides e.g. NaOH, KOH etc. are strong base. Also, Ca(OH)_{2}, Sr(OH)_{2} and Ba(OH)_{2} are strong bases.

So, KOH is a strong base, HClO_{4} is a strong acid and HNO_{2} is a weak acid.

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Tap water at room temperature has a pH of 7.2 and carbonate alkalinity of 200 mg/L (= 40 mmol/L). What is the concentration of b
UNO [17]

Answer:

the concentration of bicarbonate is <em>[HCO₃⁻] = 0,03996 M </em>and carbonate is <em>[CO₃²⁻] = 3,56x10⁻⁵ M.</em>

Explanation:

Carbonate-bicarbonate is:

HCO₃⁻ ⇄ CO₃²⁻ + H⁺ With pka = 10,25

Using Henderson-Hasselbalach formula:

pH = pka + log₁₀\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}

7,2 = 10,25 + log₁₀\frac{[CO_{3}^{2-}]}{[HCO_{3}^-]}

8,91x10⁻⁴ = \frac{[CO_{3}^{2-}]}{[HCO_{3}^-]} <em>(1)</em>

Also:

0,040 M = [CO₃²⁻] + [HCO₃⁻] <em>(2)</em>

Replacing (2) in 1:

<em>[HCO₃⁻] = 0,03996 M</em>

Thus:

<em>[CO₃²⁻] = 3,56x10⁻⁵ M</em>

I hope it helps.

4 0
3 years ago
Autopsies are only performed for a homicide
Ratling [72]
The answer to this question would be: false

Autopsies are performed to the body that didn't die from a natural cause or known disease. This will include homicide or suicide. Some case that suspected to be suicide would be a homicide that was covered by the criminal. In this case, the body is examined for any unnatural or suspicious sign that might be caused by the killer. Autopsy also needed in a malpractice case.
7 0
3 years ago
Read 2 more answers
Determine the full electron configurations:<br><br> 1. K+ (Z=19)<br><br> 2. Zn2+ (Z=30)
mixas84 [53]

Answer:

1=  K⁺= (Z=19) = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

2 = Zn²⁺= (Z = 30) =1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

Explanation:

When an atom lose or gain the electron ions are formed. There are two types of ions cation and anion.

Cation are formed when atom lose the electron.

Anion are formed when an atom gain the electron.

In given question potassium loses its valance electron and form K⁺ cation. Thus its electronic configuration will be written as,

₁₉K⁺ = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰

While the electronic configuration of potassium in neutral form is:

₁₉K = 1s² 2s² 2p⁶ 3s² 3p⁶ 4s¹

The atomic number of zinc is 30 and its electronic configuration is:

₃₀Zn= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s², 3d¹⁰

When zinc atom loses its 2 valance electrons the electron configuration will be,

₃₀Zn²⁺= 1s² 2s² 2p⁶ 3s² 3p⁶ 4s⁰, 3d¹⁰

7 0
3 years ago
Plants or animals with desirable characterstics are bred together to create improved varieties. What is this process called?
STatiana [176]

Answer:

cross breeding or selective breeding its common with dogs

Explanation:

3 0
2 years ago
Which is larger, S or S2- ?
Allisa [31]
S2- because the radius is larger
6 0
2 years ago
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