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Serga [27]
3 years ago
12

Classify each of the following substances as either a strong or weak acid, strong or weak base, or a soluble or insoluble salt.

Chemistry
1 answer:
sleet_krkn [62]3 years ago
6 0

Answer:

KOH is a strong base, HClO_{4} is a strong acid, HNO_{2} is a weak acid, NaBr is a soluble salt and PbCl_{2} is an insoluble salt

Explanation:

According to solubility rule, all chlorides, bromides and iodides of metal ions are soluble except for Pb^{2+},Ag^{+} and Hg^{+}[/tex].

Therefore NaBr is a soluble salt and PbCl_{2} is an insoluble salt.

There are seven strong acids : HCl, HBr, HI, H_{2}SO_{4}, HNO_{3}, HClO_{3} and HClO_{4}.

All group IA metal hydroxides e.g. NaOH, KOH etc. are strong base. Also, Ca(OH)_{2}, Sr(OH)_{2} and Ba(OH)_{2} are strong bases.

So, KOH is a strong base, HClO_{4} is a strong acid and HNO_{2} is a weak acid.

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CS2(1)+3O2( g)−>CO2( g)+2SO2( g)
5 0
3 years ago
Your observation and assessment data should help you _______ your curriculum A. change B. modify and individualize C. evaluate t
joja [24]
Hello,
I believe the answer is C. A and B say that it would help to change it but when we think about it data and opinions are not what people use to change a curriculum or program. Mainly they use surveys, which they didn't use here. Option D doesn't make any sense, data doesn't complement a program it supports some sort of theory which leads us to C. C is the only option where they use the data for effectiveness. Hope this helps!
4 0
3 years ago
Read 2 more answers
The units of density are kg/m2. If the density of a liquid is 760.0 kg/m' what is the specific volume? a) 1.316 x 10 m2/kg b) 1.
zlopas [31]

Answer:

The correct answer is: 1.316 . 10⁻³ m³/kg.

Explanation:

The density (ρ) of a substance is the ratio of its <em>mass (m)</em> to its <em>volume (V)</em>. At constant temperature and pressure, its value is constant and it is an intrinsic property of materials. The units of density are kg/m³.

\rho = \frac{m}{V}

The specific volume (ν) of a substance is the ratio of its <em>mass</em> to its <em>volume</em>. We can see that it is the reciprocal of density and an intrinsic property of matter as well. Therefore, the units of specific volume are m³/kg.

\nu = \frac{V}{m}=\frac{1}{\rho }

Given we know the density of the liquid, we can use this relationship to find out its specific volume:

\nu =\frac{1}{\rho }=\frac{1}{760.0kg/m^{3} } =1.316 .10^{-3} m^{3} /kg

6 0
3 years ago
How many grams would 3.36 × 1023 molecules of copper (II) sulfate (CuSO4) weigh?
Semenov [28]
Molar mass ( CuSO₄) = 159.609 g/mol

159.609 g ----------------- 6.02 x 10²³ molecules
         ? g ------------------ 3.36 x 10²³ molecules

mass = ( 3.36 x10²³) x 159.609 / 6.02 x 10²³

mass = 5.36 x 10²⁴ / 6.02 x 10²³

mass = 8.90 g 

hope this helps!
3 0
3 years ago
Read 2 more answers
If 28.0 grams of Pb(NO3)2 react with 18.0 grams of NaI, what mass of PbI2 can be produced? Pb(NO3)2 + NaI → PbI2 + NaNO3
ss7ja [257]

Answer:- 27.7 grams of PbI_2 are produced.

Solution:- The balanced equation is:

Pb(NO_3)_2+2NaI\rightarrow PbI_2+2NaNO_3

let's convert the grams of each reactant to moles and calculate the grams of the product and see which one gives least amount of the product. This least amount would be the answer as the least amount we get is from the limiting reactant.

Molar mass of Pb(NO_3)_2 = 207.2+2(14.01)+6(16)  = 331.22 gram per molmolar mass of NaI = 22.99+126.90 = 149.89 gram per molMolar mass of [tex]PbI_2 = 207.2+2(126.90) = 461 gram per mol

let's do the calculations for the grams of the product for the given grams of each of the reactant:

28.0gPb(NO_3)_2(\frac{1molPb(NO_3)_2}{331.22gPb(NO_3)_2})(\frac{1molPbI_2}{1molPb(NO_3)_2})(\frac{461gPbI_2}{1molPbI_2})

= 39.0gPbI_2

18.0gNaI(\frac{1molNaI}{149.89gNaI})(\frac{1molPbI_2}{2molNaI})(\frac{461gPbI_2}{1molPbI_2})

= 27.7gPbI_2

From above calculations, NaI gives least amount of PbI_2, so the answer is, 27.7 g of PbI_2 are produced.

8 0
3 years ago
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