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Rudik [331]
3 years ago
10

Explain why hydrogen will form an ionic bond with fluorine but only forms covalent bonds with carbon

Chemistry
2 answers:
Elan Coil [88]3 years ago
7 0

Answer : The hydrogen will form an ionic bond with fluorine but only forms covalent bonds with carbon due to electronegativity difference.

Explanation :

The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms.

According to the pauling's electronegativity rule:

If \Delta \chi=0, then the bond is non-polar.

If \Delta \chi\leq 1.7, then the bond will be covalent.

If \Delta \chi>1.7, then the bond will be ionic.

As we know that:

Electronegativity for fluorine = 3.98

Electronegativity for hydrogen = 2.1

Electronegativity for carbon = 2.55

Electronegativity difference between HF:

\Delta \chi=\chi_{F}-\chi_{H}\\\\\Delta \chi=3.98-2.1=1.88

Electronegativity difference between CH:

\Delta \chi=\chi_{C}-\chi_{H}\\\\\Delta \chi=2.55-2.1=0.45

As, electronegativity difference of HF is more than 1.7. Thus, the bond between fluorine and hydrogen is ionic bond.

As, electronegativity difference of CH is less than 1.7. Thus, the bond between carbon and hydrogen is covalent bond.

vaieri [72.5K]3 years ago
4 0

A fluorine atom has seven valence electrons. ... Carbon will then have five valence electrons (its four and the one its sharing with fluorine). Covalently sharing two electrons is also known as a “single bond.” Carbon will have to form four single bonds with four different fluorine atoms to fill its octet.

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The molarity (M) of an aqueous solution containing 22.5 g of sucrose (C12H22O11) in 35.5 mL of solution is ________.
Nonamiya [84]

Answer:

1.86 M

Explanation:

From the question given above, the following data were obtained:

Mass of sucrose (C12H22O11) = 22.5 g

Volume of solution = 35.5 mL

Molarity of solution =?

Next, we shall determine the number of mole in 22.5 g of sucrose (C12H22O11). This can be obtained as follow:

Mass of sucrose (C12H22O11) = 22.5 g

Molar mass of C12H22O11 = (12×12) + (22×1) + (16×11)

= 144 + 22 + 176

= 342 g/mol

Mole of C12H22O11 =?

Mole = mass /Molar mass

Mole of C12H22O11 = 22.5 /342

Mole of sucrose (C12H22O11) = 0.066 mole

Next, we shall convert 35.5 mL to litres (L). This can be obtained as follow:

1000 mL = 1 L

Therefore,

35.5 mL = 35.5 mL × 1 L / 1000 mL

35.5 mL = 0.0355 L

Thus, 35.5 mL is equivalent to 0.0355 L.

Finally, we shall determine the molarity of the solution as follow:

Mole of sucrose (C12H22O11) = 0.066 mole

Volume of solution = 0.0355 L.

Molarity of solution =?

Molarity = mole /Volume

Molarity of solution = 0.066/0.0355

Molarity of solution = 1.86 M

Therefore, the molarity of the solution is 1.86 M.

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Answer:

See explanation.

Explanation:

Hello there!

In this case, considering the given information, it is not possible to figure out such order of reaction with respect to water as it is not involved in the given chemical reaction:

2E(g)+ F(g)+O(g)_

However, we can say that the order of reaction is 2 with respect to E (power of 2 in the rate law), 1 with respect to F (power of 1 in the rate law) and 0 with respect to O (power of 0 or not present in the rate law).

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