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3 years ago

Explain why hydrogen will form an ionic bond with fluorine but only forms covalent bonds with carbon

2 answers:

7 0

Answer : The hydrogen will form an ionic bond with fluorine but only forms covalent bonds with carbon due to electronegativity difference.

Explanation :

The type of bonding between the atoms forming a compound is determined by using the electronegativity difference between the atoms.

According to the pauling's electronegativity rule:

If $\Delta \chi=0$ , then the bond is non-polar.

If $\Delta \chi\leq 1.7$ , then the bond will be covalent.

If $\Delta \chi>1.7$ , then the bond will be ionic.

As we know that:

Electronegativity for fluorine = 3.98

Electronegativity for hydrogen = 2.1

Electronegativity for carbon = 2.55

Electronegativity difference between HF:

$\Delta \chi=\chi_{F}-\chi_{H}\\\\\Delta \chi=3.98-2.1=1.88$

Electronegativity difference between CH:

$\Delta \chi=\chi_{C}-\chi_{H}\\\\\Delta \chi=2.55-2.1=0.45$

As, electronegativity difference of HF is more than 1.7. Thus, the bond between fluorine and hydrogen is ionic bond.

As, electronegativity difference of CH is less than 1.7. Thus, the bond between carbon and hydrogen is covalent bond.

vaieri [72.5K]3 years ago

4 0

A fluorine atom has seven valence electrons. ... Carbon will then have five valence electrons (its four and the one its sharing with fluorine). Covalently sharing two electrons is also known as a “single bond.” Carbon will have to form four single bonds with four different fluorine atoms to fill its octet.

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Describe the importance of Antoine Lavoisier's work with combustion. Include in the answer the title he was given and what he di

Komok [63]

Answer:

Explanation:

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3 years ago

Which is a common unbalanced force acting on objects in motion?

Semmy [17]

Answer:

a. friction

Explanation:

What is a common unbalanced force acting in motion? Common forces that are often unbalanced include the force of gravity and applied forces. When these forces are unbalanced, objects accelerate, change their position and find new configurations for which all forces are again balanced.

Friction is a kind of force.

5 0

3 years ago

Read 2 more answers

Question 1(Multiple Choice Worth 4 points)

zubka84 [21]

<u>Answer </u>

Answer 1 : 28.9 g of CO is needed.

Answer 2 : Six moles of $H_{2}O$ over Nine moles of $O_{2}$

Answer 3 : Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of $Fe_{2}O_{3}$ .

Answer 4 : Mass of $O_{2}$ = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Answer 5 : 8.4 moles of sodium cyanide (NaCN) would be needed.

<u>Solution </u>

Solution 1 : Given,

Given mass of $Fe_{2}O_{3}$ = 55 g

Molar mass of $Fe_{2}O_{3}$ = 159.69 g/mole

Molar mass of CO = 28.01 g/mole

Moles of $Fe_{2}O_{3}$ = $\frac{\text{ Given mass of } Fe_{2}O_{3}}{\text{ Molar mass of } Fe_{2}O_{3}}$ = $\frac{55 g}{159.69 g/mole}$ = 0.344 moles

Balanced chemical reaction is,

$Fe_{2}O_{3}(s)+3CO(g)\rightarrow 2Fe(s)+3CO_{2}(g)$

From the given reaction, we conclude that

1 mole of $Fe_{2}O_{3}$ gives → 3 moles of CO

0.344 moles of $Fe_{2}O_{3}$ gives → 3 × 0.344 moles of CO

= 1.032 moles

Mass of CO = Number of moles of CO × Molar mass of CO

= 1.032 × 28.01

= 28.90 g

Solution 2 : The balanced chemical reaction is,

$2C_{3}H_{6}+9O_{2}\rightarrow 6CO_{2}+6H_{2}O$

From the given reaction, we conclude that the Six moles of $H_{2}O$ over Nine moles of $O_{2}$ is the correct option.

Solution 3 : The balanced chemical reaction is,

$4Fe+3O_{2}\rightarrow 2Fe_{2}O_{3}$

From the given balanced reaction, we conclude that Four over two fraction can be used for the mole ratio to determine the mass of Fe from a known mass of $Fe_{2}O_{3}$ .

Solution 4 : Given,

Given mass of $Zn(ClO_{3})_{2}$ = 150 g

Molar mass of $Zn(ClO_{3})_{2}$ = 232.29 g/mole

Molar mass of $O_{2}$ = 31.998 g/mole

Moles of $Zn(ClO_{3})_{2}$ = $\frac{\text{ Given mass of }Zn(ClO_{3})_{2} }{\text{ Molar mass of } Zn(ClO_{3})_{2}}$ = $(\frac{150\times 1}{232.29})moles$

The balanced chemical equation is,

$Zn(ClO_{3})_{2}}\rightarrow ZnCl_{2}+3O_{2}$

From the given balanced equation, we conclude that

1 mole of $Zn(ClO_{3})_{2}$ gives → 3 moles of $O_{2}$

$(\frac{150\times 1}{232.29})moles$ of $Zn(ClO_{3})_{2}$ gives → $[(\frac{150\times 1}{232.29})\times 3] moles$ of $O_{2}$

Mass of $O_{2}$ = Number of moles of $O_{2}$ × Molar mass of $O_{2}$ = $[(\frac{150\times 1}{232.29})\times 3] \times 31.998 grams$

Therefore, the mass of $O_{2}$ = (150 × 3 × 31.998) ÷ (232.29 × 1) grams

Solution 5 : Given,

Number of moles of $Na_{2}SO_{4}$ = 4.2 moles

Balanced chemical equation is,

$H_{2}SO_{4}+2NaCN\rightarrow 2HCN+Na_{2}SO_{4}$

From the given chemical reaction, we conclude that

1 mole of $Na_{2}SO_{4}$ obtained from 2 moles of NaCN

4.2 moles of $Na_{2}SO_{4}$ obtained → 2 × 4.2 moles of NaCN

Therefore,

The moles of NaCN needed = 2 × 4.2 = 8.4 moles

3 0

3 years ago

Read 2 more answers

Which of the following contains an atom that does not obey the octet rule? BrF3 SiO2 NaCl BrF

mrs_skeptik [129]

The octet rule signifies towards the capability of the atoms to prefer to exhibit eight electrons in the valence shell. In case, when the atoms possess lesser than eight electrons, they seem to react and produce more stable components. While discussing octet rule, one does not consider d or f electrons.

According to the octet rule, the atoms of the prime-group elements seem to bind in such a manner that each atom exhibit eight electrons in its valence shell, providing it the similar electronic configuration as a noble gas.

In the given question, in BrF3, fluorine follows octet rule, while bromine does not follow the octet rule.

5 0

3 years ago

Read 2 more answers

Calculate the weight of the rocks in the photo. The measurement from the scale is given in the caption. (textbook page 8 picture

vitfil [10]

Answer:

The correct answer is - 4.9 kg x m/s^2.

Explanation:

The weight of any object is the mass of the object in specific gravity applied to the object. It can be represented by the F=ma where F is the force applied on the earth by the gravity (a) and mass of the object (m).

Solution:

F = ma

F = 0.5*9.8 kg x m/s^2.

= 4.9 kg x m/s^2.

4 0

3 years ago