Answer:
0.0252mol/L
Explanation:
The following data were obtained obtained from the question:
Volume of solution = 284mL = 284/1000 = 0.284L
Mole of CuSO4 = 7.157 × 10^-3 mol
Molarity =?
Molarity = mole/Volume
Molarity = 7.157x10^-3 /0.284
Molarity = 0.0252mol/L
The concentration of the solution is 0.0252mol/L
Answer:
Explanation:
Hello!
In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):
Next, since the VdW equation requires the molar volume, we proceed as shown below:
Now, we use its definition:
Thus, by plugging in we obtain:
Thus, the pressure difference is:
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Answer:
Moles= 10.55*10^29ǜ.02*10^23
=1.75*10^6 moles
Moles= mass/molar mass
1.75*10^6=mass/ 183
Mass= 320*10^6 g