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Aneli [31]
3 years ago
9

Neodymium battery + sulfuric acid ——> neodymium sulfate + iron sulfate + boron + hydrogen. I have 5g of Nd2Fe14B and enough H

2SO4, how much NdSO4 will I get?
Chemistry
1 answer:
iren2701 [21]3 years ago
7 0

Mass of Nd₂(SO₄)₃ : 2.653 g

<h3>Further explanation</h3>

Reaction

Nd₂Fe₁₄B + 17H₂SO₄ → Nd₂(SO₄)₃ + 14FeSO₄ + B + 17H₂

5 g Nd₂Fe₁₄B

MW = 2. 144,242 + 14. 55.845 + 10.811

MW = 288.484 + 781.83+10.811=1081.125 g/mol

mol :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{5}{1081.125}=0.0046

mol Nd₂Fe₁₄B = mol Nd₂(SO₄)₃=0.0046

so mass of Nd₂(SO₄)₃ :

MW Nd₂(SO₄)₃ = 2.144.242+3.32,065+12.15,999

MW = 288.484+96.195+191.988=576.667 g/mol

\tt mass=mol\times MW\\\\mass=0.0046\times 576.667\\\\mass=2.653~g

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Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).
Pani-rosa [81]

The question is incomplete, here is the complete question:

Calculate the solubility of hydrogen in water at an atmospheric pressure of 0.380 atm (a typical value at high altitude).

Atmospheric Gas         Mole Fraction      kH mol/(L*atm)

           N_2                         7.81\times 10^{-1}         6.70\times 10^{-4}

           O_2                         2.10\times 10^{-1}        1.30\times 10^{-3}

           Ar                          9.34\times 10^{-3}        1.40\times 10^{-3}

          CO_2                        3.33\times 10^{-4}        3.50\times 10^{-2}

          CH_4                       2.00\times 10^{-6}         1.40\times 10^{-3}

          H_2                          5.00\times 10^{-7}         7.80\times 10^{-4}

<u>Answer:</u> The solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

<u>Explanation:</u>

To calculate the partial pressure of hydrogen gas, we use the equation given by Raoult's law, which is:

p_{\text{hydrogen gas}}=p_T\times \chi_{\text{hydrogen gas}}

where,

p_A = partial pressure of hydrogen gas = ?

p_T = total pressure = 0.380 atm

\chi_A = mole fraction of hydrogen gas = 5.00\times 10^{-7}

Putting values in above equation, we get:

p_{\text{hydrogen gas}}=0.380\times 5.00\times 10^{-7}\\\\p_{\text{hydrogen gas}}=1.9\times 10^{-7}atm

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{H_2}=K_H\times p_{H_2}

where,

K_H = Henry's constant = 7.80\times 10^{-4}mol/L.atm

p_{H_2} = partial pressure of hydrogen gas = 1.9\times 10^{-7}atm

Putting values in above equation, we get:

C_{H_2}=7.80\times 10^{-4}mol/L.atm\times 1.9\times 10^{-7}atm\\\\C_{CO_2}=1.48\times 10^{-10}M

Hence, the solubility of hydrogen gas in water at given atmospheric pressure is 1.48\times 10^{-10}M

4 0
3 years ago
5. What is the systemic name for the following structure?
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Answer:

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Explanation:

since the substituents are on same side, it call cis. Followed by the name.

5 0
3 years ago
If you want to prepare 80.0 mL of 4.00M acid ,How many mL of 12.4 M HCl are required ?
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M_{A}V_{A}=M_{B}V_{B}\\(80.0)(4.00)=V_{B}(12.4)\\V_{B}=\frac{(80.0)(4.00)}{12.4} \approx \boxed{25.8 \text{ mL}}

5 0
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Answer:

A) measuring mass of metal used in a reaction

Explanation:

Quantitive observations is data involving statistics and numerical values.

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All atoms consist of a nucleus with protons and neutrons that is surrounded by a sea of electrons. If Uranium-235 is bombarded with a neutron then the atom's atomic number will remain the same but its mass will increase by 1 unit. Thus, it will temporarily become Uranium-236. 
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