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Aneli [31]
3 years ago
9

Neodymium battery + sulfuric acid ——> neodymium sulfate + iron sulfate + boron + hydrogen. I have 5g of Nd2Fe14B and enough H

2SO4, how much NdSO4 will I get?
Chemistry
1 answer:
iren2701 [21]3 years ago
7 0

Mass of Nd₂(SO₄)₃ : 2.653 g

<h3>Further explanation</h3>

Reaction

Nd₂Fe₁₄B + 17H₂SO₄ → Nd₂(SO₄)₃ + 14FeSO₄ + B + 17H₂

5 g Nd₂Fe₁₄B

MW = 2. 144,242 + 14. 55.845 + 10.811

MW = 288.484 + 781.83+10.811=1081.125 g/mol

mol :

\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{5}{1081.125}=0.0046

mol Nd₂Fe₁₄B = mol Nd₂(SO₄)₃=0.0046

so mass of Nd₂(SO₄)₃ :

MW Nd₂(SO₄)₃ = 2.144.242+3.32,065+12.15,999

MW = 288.484+96.195+191.988=576.667 g/mol

\tt mass=mol\times MW\\\\mass=0.0046\times 576.667\\\\mass=2.653~g

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