Answer:
f(x) = 4.35 +3.95·sin(πx/12)
Step-by-step explanation:
For problems of this sort, a sine function is used that is of the form ...
f(x) = A + Bsin(2πx/P)
where A is the average or middle value of the oscillation, B is the one-sided amplitude, P is the period in the same units as x.
It is rare that a tide function has a period (P) of 24 hours, but we'll use that value since the problem statement requires it. The value of A is the middle value of the oscillation, 4.35 ft in this problem. The value of B is the amplitude, given as 8.3 ft -4.35 ft = 3.95 ft. Putting these values into the form gives ...
f(x) = 4.35 + 3.95·sin(2πx/24)
The argument of the sine function can be simplified to πx/12, as in the Answer, above.
Answer:a)680cu.ft
b)180cu.ft
Hope this helped you...
Step-by-step explanation:
I guess the number 2 is to indicate the question...
Then the equation would be 1/3 - 1/2x = -2/3
1/3 - 1/2x - 1/3 = -2/3 - 1/3
-1/2x = -3/3
-1/2x = -1
-1/2x *2 = - 1*2
-x = -2
-x * -1 = -2 * -1
x = 2
Good luck
Answer:
the answer is C.
Step-by-step explanation:
3(2/3)
=3×2/3
=2×3/3
=2
Answer:
your answer is 18
Step-by-step explanation:
