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Y_Kistochka [10]
3 years ago
14

Radio waves and microwaves are similar because they both have

Physics
1 answer:
tekilochka [14]3 years ago
4 0

The correct answer is

b. low frequencies and low energy.

In fact, microwaves and radio waves have frequency up to 10^{10}-10^{11} Hz, which are really low compared, for instance, to the frequency of gamma rays (10^{20} Hz). Moreover, the energy of an electromagnetic wave is directly proportional to its frequency:

E=hf

where h is the Planck constant and f the frequency; therefore, low frequency means also low energy.

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Calculate the amount of heat needed to melt 35.0 g of ice at 0 ºC.Express your answer in kilojoules
PolarNik [594]
The amount of heat will be equal to Lm.

Where L is the latent heat of fusion and m is mass of the ice.

Latent heat of ice = 80cal/g.

So the amount of heat required here will be 35× 80cal

= 2,800 cal.
6 0
3 years ago
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Answer all these questions
Kazeer [188]

Answer:

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If the amplitude increases the volume increases and vice versa.

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A light bulb dissipates 100 Watts of power when it is supplied a voltage of 220 volts.
ycow [4]

Given Information:

Power = P = 100 Watts

Voltage = V = 220 Volts

Required Information:

a) Current = I = ?

b) Resistance = R = ?

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a) Current = I = 0.4545 A

b) Resistance = R = 484 Ω

Explanation:

According to the Ohm’s law, the power dissipated in the light bulb is given by

P = VI

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and P is the power dissipated in the light bulb.

Re-arranging the above equation for current I yields,

I = \frac{P}{V}  \\\\I = \frac{100}{220} \\\\I = 0.4545 \: A \\\\

Therefore, 0.4545 A current is flowing through the light bulb.

According to the Ohm’s law, the voltage across the light bulb is given by

V = IR

Where V is the voltage across the light bulb, I is the current flowing through the light bulb and R is the resistance of the light bulb.

Re-arranging the above equation for resistance R yields,

R = \frac{V}{I} \\\\R = \frac{220}{0.4545} \\\\R = 484 \: \Omega

Therefore, the resistance of the bulb is 484 Ω

3 0
3 years ago
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Crazy boy [7]

Answer:

making sure that you change one factor at a time while keeping all other conditions the same

Explanation:

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2 years ago
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Lapatulllka [165]

Answer:

The answer is 11N to the right

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Because 4N-3N= 1N

Therefore, 12N-1N=11N

The netforce is 11N to the right, because the greatest force is 12N to the right so it is more likely that the object is being pulled to the right.

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