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katovenus [111]
3 years ago
9

An isolated system allows which of the following to enter or exit

Physics
2 answers:
BabaBlast [244]3 years ago
8 0
I think it's A but not 100% sure though.
MariettaO [177]3 years ago
7 0

Answer:

Neither energy nor matter

Explanation:

A system is defined as the part of the universe. In thermodynamics, systems are of three types i.e.

1. Open System : In an open system, both energy and matter can freely exchange with surrounding. For example- boiling water in an open pan transfers both energy and matter.

2. Closed system : In a closed system, only energy is exchanged with the surrounding. For example- boiling water with a lid on the pan exchanges only energy with the surrounding.

3. Isolated system : In an isolated system, neither energy nor matter exchanges with the surrounding. For example : a thermos flask does not exchange energy and matter with the surrounding.

Hence, the correct option is (a) " neither energy nor matter ".

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Thales of Miletus lived during now.

Explanation:

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1) Classify each of the following as either a solid, liquid or gas at room temperature.
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air gas

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2 years ago
A speeding motorist traveling down a straight highway at 100 km/h passes a parked police car. It takes the police constable 1.0
Lubov Fominskaja [6]

Answer:

t = 7.5 s

Explanation:

The distance traveled by the car at the time of meeting of the two cars must be the same. First, we calculate the distance traveled by the police car. For that we use 2nd equation of motion. Here, we take the time when police car starts to be reference. So,

s₁ = Vi t + (0.5)gt²

where,

s₁ = distance traveled by police car

Vi = Initial Velocity = 0 m/s

t = time taken

Therefore,

s₁ = (0 m/s)(t) + (0.5)(9.8 m/s²)t²

s₁ = 4.9 t²

Now, we calculate the distance traveled by the car. For constant speed and time to be 1 second more than the police car time, due to car starting time, we get:

s₂ = Vt = V(t + 1)

where,

s₂ = distance traveled by car

V = Velocity of car = (100 km/h)(1000 m/1 km)(1 h/ 3600 s) = 27.78 m/s

Therefore,

s₂ = 27.78 t + 27.78

Now, we know that at the time of meeting:

s₁ = s₂

4.9 t² = 27.78 t + 27.78

4.9 t² - 270.78 t - 27.78 = 0

solving the equation and choosing the positive root:

t = 6.5 s

since, we want to know the time from the moment car crossed police car. Therefore, we add 1 second of starting time in this.

t = 6.5 s + 1 s

<u>t = 7.5 s</u>

6 0
3 years ago
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