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Anon25 [30]
2 years ago
6

An object with a momentum of 1600 kg m/s slows down and its new momentum is 900 kg m/s. What is the magnitude of the impulse tha

t caused this change?
Impulse (J) Formula: J= FΔT= MΔV
Physics
1 answer:
Anika [276]2 years ago
8 0
Hehudididididiririririridudhd
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A uniformly charged ring of radius 10.0 cm has a total charge of 50.0 μC Find the electric field on the axis of the ring at 30.0
Grace [21]

Answer: 4.27 *10^6 N/C

Explanation: In order to calculate the electric field along the axis of charged ring we have to use the following expression:

E=k*x/(a^2+x^2)^3/2    where a is the ring radius and x the distance to the point measured from the center of the ring.

Replacing the data we have:

E= (9* 10^9* 0.3* 50 * 10^-6)/(0.1^2+0.3^2)^3/2

then

E=4.27 * 10^6 N/C

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Explanation:

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Natali5045456 [20]

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True

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If this is about simple machines the answer is: Inclined plane
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