Question

A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n = 1) interference minimum (destructive)? (speed of sound = 343 m/s. Unit = m)

Answer 1

Answer:

4.00 is correct

Explanation:

I think

Answer 2

Given :

A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker.

To Find :

The wavelength of the first (n = 1) interference minimum (destructive).

Solution :

Since speaker are identical so they are in same phase.

For first destructive construction difference between the distance should be equal to half the wavelength .

So, $8-6 = \dfrac{\lambda}{2}\\\\\lambda = 4 \ m$

Frequency is given by :

$\nu = \dfrac{343}{4}\ Hz\\\\\nu = 85.75 \ Hz$

Hence, this is the required solution.