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Zielflug [23.3K]
2 years ago
15

A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker. What is the wavelength of the first (n = 1) interfe

rence minimum (destructive)? (speed of sound = 343 m/s. Unit = m)
Physics
2 answers:
kirza4 [7]2 years ago
4 0

Answer:

4.00 is correct

Explanation:

I think

Reika [66]2 years ago
3 0

Given :

A person stands 6.00 m from a speaker, and 8.00 m from an identical speaker.

To Find :

The wavelength of the first (n = 1) interference minimum (destructive).

Solution :

Since speaker are identical so they are in same phase.

For first destructive construction difference between the distance should be equal to half the wavelength .

So, 8-6 = \dfrac{\lambda}{2}\\\\\lambda = 4 \ m

Frequency is given by :

\nu = \dfrac{343}{4}\ Hz\\\\\nu = 85.75 \ Hz

Hence, this is the required solution.

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2 years ago
A swimmer bounces almost straight up from a diving board and falls vertically feet first into a pool.she starts with a speed of
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Answer:

a) 1.20227 seconds

b) 0.98674 m

c) 7.3942875 m/s

Explanation:

t = Time taken

u = Initial velocity = 4.4 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

v=u+at\\\Rightarrow 0=4.4-9.81\times t\\\Rightarrow \frac{-4.4}{-9.81}=t\\\Rightarrow t=0.44852\ s

s=ut+\frac{1}{2}at^2\\\Rightarrow s=4.4\times 0.44852+\frac{1}{2}\times -9.81\times 0.44852^2\\\Rightarrow s=0.98674\ m

b) Her highest height above the board is 0.98674 m

Total height she would fall is 0.98674+1.8 = 2.78674 m

s=ut+\frac{1}{2}at^2\\\Rightarrow 2.78674=0t+\frac{1}{2}\times 9.81\times t^2\\\Rightarrow t=\sqrt{\frac{2.78674\times 2}{9.81}}\\\Rightarrow t=0.75375\ s

a) Her feet are in the air for 0.75375+0.44852 = 1.20227 seconds

v=u+at\\\Rightarrow v=0+9.81\times 0.75375\\\Rightarrow v=7.3942875\ m/s

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3 0
3 years ago
A drunken sailor stumbles 550 meters north, 500 meters northeast, then 450 meters northwest. What is the total displacement and
cluponka [151]

Answer:

Resultant displacement = 1222.3 m

Angle is 88.3 degree from +X axis.

Explanation:

A = 550 m north

B = 500 m north east

C = 450 m north west

Write in the vector form

A = 550 j

B = 500 (cos 45 i + sin 45 j ) = 353.6 i + 353.6 j

C = 450 ( - cos 45 i + sin 45 j ) = - 318.2 i + 318.2 j

Net displacement is given by

R = (353.6 - 318.2) i + (550 + 353.6 + 318.2) j

R = 35.4 i + 1221.8 j

The magnitude is

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The direction is given by

tan\theta =\frac{1221.8}{35.4}\\\\\theta = 88.3^{o}

3 0
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