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Dafna1 [17]
3 years ago
11

What would happen when two or more capacitors are connected in series across a potential difference, then

Physics
2 answers:
anyanavicka [17]3 years ago
6 0

Answer:

The Current Iₜ = I₁ = I₂ = I₃

Charge Qₜ = Q₁ = Q₂ = Q₃

Potential difference Vₜ = V₁ + V₂ + V₃

Capacitance 1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃

Explanation:

According to the attached image;

For series arrangements of capacitors, the current flowing through each of the capacitors are the same and equal to the total current flowing through the circuit;

Iₜ = I₁ = I₂ = I₃

Also the charge storage by each capacitor is equal;

Qₜ = Q₁ = Q₂ = Q₃

The potential difference across each of the capacitors sum up to the total voltage across the circuit;

Vₜ = V₁ + V₂ + V₃

The reciprocal of the total capacitance equals the sum of the reciprocal of capacitances of each of the capacitors;

1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃

crimeas [40]3 years ago
6 0

Answer:

1) the net potential difference of the circuit will be the sum of all the potential difference of all the individual capacitors that are connected together.

2) The net capacitance in the circuit would be lesser than that of the capacitance of the individual capacitors.

3) the charges on the individual capacitors will remain the same.

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You are standing a distance of 17.0 meters from the center of a merry-go-round. The merry-go-round takes 9.50 seconds to go comp
GenaCL600 [577]

Answer:

(a)11.24 m/s

(b)7.44 m/s

(c)409 N

(d)539.55\mu

(e) 0

Explanation:

The period for 1 circle 2\pi of the merry go around is 9.5s. It means the angular speed is:

\omega = \theta / t = 2\pi / 9.5 \approx 0.661 rad/s

(a)The speed is

v = \omega * R = 0.661 * 17 = 11.24 m/s

(b) Centripetal acceleration:

a = \frac{v^2}{R} = \frac{11.24^2}{17} = 7.44 m/s^2

(c) Magnitude of the force that keeps you go around at this acceleration

F = ma = 55 * 7.44 = 409 N

(d) let the coefficient of friction by \mu. The frictional force shall be this coefficient multiplied by normal force reverting gravity of the man

F_f = mg\mu = 55*9.81\mu = 539.55\mu

3 0
3 years ago
Two blocks with different temperatures had entropies of 10 J/K and 30 J/K before they were brought in contact. What can you say
True [87]

Answer:

a. Ssystem  > 40 J/K

Explanation:

Given that

The entropy of first block = 10 J/K

The entropy of second block = 30 J/K

When two bodies come into contact with each other, the entropy of the combined system will increase and the entropy sum remains unchanged: According to the Second law of thermodynamics.The entropy of the system will be greater than 40  J/K.

Therefore the answer is a.

Ssystem  > 40 J/K

6 0
3 years ago
(TCO 5) The relationship between Celsius (º C) and Fahrenheit (º F) degree of measuring temperature is linear. Find the linear e
gtnhenbr [62]

Answer:

C=-\dfrac{10}{17}(F-32)

Explanation:

Given that

32° F corresponds to 0 °C.  ---Point 1

212° F corresponds to 100 °C.----Point 2

We know that if two point is given that equation of line can be found as

y-y_1=\dfrac{y_2-y_1}{x_2-x_2}(x-x_1)

Lets C in y- direction and F in x- direction,so we can say that

C-C_1=\dfrac{C_2-C_1}{F_2-F_2}(F-F_1)

C-0=\dfrac{100-0}{32-212}(F-32)

C=-\dfrac{10}{17}(F-32)

So the linear relationship is

C=-\dfrac{10}{17}(F-32)

8 0
3 years ago
an airplane travels 2100 km at a speed of 1000 km/h for the next 1300 km. whatis the average speed for this plane trip?
Vanyuwa [196]

wouldn't it be 1000 km/h considering the plane was travelling the same speed for over half the trip?

4 0
3 years ago
I have one but can some one help with the second one?​
alisha [4.7K]

Answer:

it is a, direction

5 0
3 years ago
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