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3 years ago

What would happen when two or more capacitors are connected in series across a potential difference, then

Physics

2 answers:

anyanavicka [17]3 years ago

6 0

Answer:

The Current Iₜ = I₁ = I₂ = I₃

Charge Qₜ = Q₁ = Q₂ = Q₃

Potential difference Vₜ = V₁ + V₂ + V₃

Capacitance 1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃

Explanation:

According to the attached image;

For series arrangements of capacitors, the current flowing through each of the capacitors are the same and equal to the total current flowing through the circuit;

Iₜ = I₁ = I₂ = I₃

Also the charge storage by each capacitor is equal;

Qₜ = Q₁ = Q₂ = Q₃

The potential difference across each of the capacitors sum up to the total voltage across the circuit;

Vₜ = V₁ + V₂ + V₃

The reciprocal of the total capacitance equals the sum of the reciprocal of capacitances of each of the capacitors;

1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃

crimeas [40]3 years ago

6 0

Answer:

1) the net potential difference of the circuit will be the sum of all the potential difference of all the individual capacitors that are connected together.

2) The net capacitance in the circuit would be lesser than that of the capacitance of the individual capacitors.

3) the charges on the individual capacitors will remain the same.

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$\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}$

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$\small\bm{The \: angle \: between \: the \: vector \: }$

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