Answer:
The Current Iₜ = I₁ = I₂ = I₃
Charge Qₜ = Q₁ = Q₂ = Q₃
Potential difference Vₜ = V₁ + V₂ + V₃
Capacitance 1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃
Explanation:
According to the attached image;
For series arrangements of capacitors, the current flowing through each of the capacitors are the same and equal to the total current flowing through the circuit;
Iₜ = I₁ = I₂ = I₃
Also the charge storage by each capacitor is equal;
Qₜ = Q₁ = Q₂ = Q₃
The potential difference across each of the capacitors sum up to the total voltage across the circuit;
Vₜ = V₁ + V₂ + V₃
The reciprocal of the total capacitance equals the sum of the reciprocal of capacitances of each of the capacitors;
1/Cₜ = 1/C₁ + 1/C₂ + 1/C₃
Answer:
the magnitude of the magnetic force on the wire is 0.2298 N
Explanation:
Given the data in the question;
we know that, the magnitude of magnetic force is given as;
|F | = I(
×
)
given that
I = 2.6 A
= 0.17
= 0.52
so we substitute
|F | = 2.6( 0.17i" × 0.52j" )
|F | = 0.2298 N
Therefore, the magnitude of the magnetic force on the wire is 0.2298 N