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3 years ago

Put these 5 events in the correct order. Formation of Atoms, Time begins, Formation of Galaxies

Physics

1 answer:

Ivahew [28]3 years ago

7 0

Answer:

Time begins, Formation of subatomic particles, Formation of Atoms, Formation of stars, Formation of Galaxies

Explanation:

At the beginning right after the big bang time starts then sub-atomic particles forms i.e. protons, neutrons from this atoms form and after that stars and galaxies form.

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A circular saw blade with radius 0.175 m starts from rest and turns in a vertical plane with a constant angular acceleration of

ANEK [815]

Answer:

The distance the piece travel in horizontally axis is

L=3.55m

Explanation:

$a=2 \frac{rev}{s^{2}} \\h=0.820m\\r = 0.125 m
\\d=150rev$

$d= 155 rev = 155(2\pi ) = 310\pi rad$

$a= 2.0 \frac{rev}{s^{2} } = 2.0(2\pi ) = 4.0\pi \frac{rev}{s^{2} }$

$d=d_{i}+vo*t+\frac{1}{2}*a*t^{2} \\ di=0\\vo=0\\d=\frac{1}{2}*a*t^{2}\\t=\sqrt{\frac{2*d}{a}}\\t=\sqrt{\frac{2*310 rad}{4\frac{rad}{s^{2}}}} \\t=12.449$

$w=a*t\\w=4\frac{rad}{s^{2}}*12.449s\\ w=49.79 \frac{rad}{s}$

Now the angular velocity is the blade speed so:

$V=w*r\\V=49.79 \frac{rad}{s}*0.175m\\V=8.7 \frac{m}{s}$

assuming no air friction effects affect blade piece:

time for blade piece to fall to floor

$t=\sqrt{\frac{2*h}{g}}\\t=\sqrt{\frac{2*0.820m}{9.8\frac{m}{s^{2} } }}\\t=0.409s$

Now is the same time the piece travel horizontally

$L=t*V\\L=0.409s*8.7\frac{m}{s}\\L=3.55m$

blade piece travels HORIZONTALLY = (24.5)(0.397) = 9.73 m ANS

6 0

4 years ago

Madeline is measuring wavelengths. Look at her notes above. What mistakes has she made in her measurement? What should she do di

aleksklad [387]

She didn’t even measure a wavelength. she should measure crest to crest.

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3 years ago

The moon and other satellites rotate around the earth. Identify the force that keeps these satellites in orbit. A) gravity B) fr

RoseWind [281]

The force is gravity

4 0

3 years ago

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A student swings a 5.0 Kg pail of water in a vertical circle of radius 1.3m. What is the minimum speed at the top of the circle

cestrela7 [59]

Answer:

v = 3.57 m / s

Explanation:

Let's use Newton's second law in the upper part of the circle, with the minimum speed so that the water does not rest on the circle, that is, the normal is zero

W = m a

acceleration is centripetal

a = v² / r

let's substitute

mg = m v² / r

v = $\sqrt{r g }$

let's calculate

v = $\sqrt{1.3 \ 9.8}$ ra 1.3 9.8

v = 3.57 m / s

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3 years ago

A firecracker shoots up from a hill 160 feet high with an initial speed of 90 feet per second. Using the formula H(t) = −16t2 +

sammy [17]

When the firecracker hits the ground, H(t) = 0.0 = -16t^2 + 90t + 160Using the quadratic formula,t = (-90 +- sqrt(90^2 - 4(-16)(160))) / 2(-16)t = -1.42 ort = 7.04
The negative time is extraneous. Therefore,t = 7.04 s.

4 0

3 years ago

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