Answer:
5 = a whole big mac right so if you get a triple big mac divide the big mac to the other one
Step-by-step explanation:
23 3/4. because if it was 0.25, then you know that it is a quarter, 0.50 is half, therefore 0.75 is three quarters
Answer:
Explanation Below
Step-by-step explanation:
1. -4 + | x - 1 | = 3
= -4 + | x - 1 | + 4 = 3 + 4
= | x - 1 | = 7
= x - 1 = -7 or x - 1 = 7
= x = -6 or x = 8
2. 6 + 4 | 2x + 6| = 14
= 6 + 4 | 2x + 6 | - 6 = 14 - 6
= 4 | 2x + 6 | = 8
= 4 | 2x + 6 | / 4 = 8/4
= 2x + 6 = -2 or 2x + 6 = 2
= x = -4 or x = -2
3. -10 + | -6 - x | = 1
= -10 + | -6 + x | + 10 = 1 + 10
= | -6 - x | = 11
= -6 - x = -11 or -6 - x = 11
= x = -17 or x = 5
4. | 7 - 2x | + 4 = 5
= | 7 - 2x | + 4 - 4 = 5 - 4
= | 7 - 2x | = 1
= 7 - 2x = -1 or 7 - 2x = 1
= x = 3 or x = 4
Here are the Steps:
SOLVING EQUATIONS CONTAINING ABSOLUTE VALUE(S)
Step 1: Isolate the absolute value expression.
Step2: Set the quantity inside the absolute value notation equal to + and - the quantity on the other side of the equation.
Step 3: Solve for the unknown in both equations.
Step 4: Check your answer analytically or graphically.
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Answer:
Binomial
There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Step-by-step explanation:
For each copy of the document, there are only two possible outcomes. Either it is defective, or it is not. This means that we can solve this problem using the binomial probability distribution.
Binomial probability distribution:
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And p is the probability of X happening.
In this problem
Of the 20 copies, 2 are defective, so
.
What is the probability that you will encounter neither of the defective copies among the 10 you examine?
This is P(X = 0) when
.


There is a 34.87% probability that you will encounter neither of the defective copies among the 10 you examine.
Answer:
<u>x^3-8x^2+5x+14</u>
Step-by-step explanation:
(x+1)(x-2)(x-7)
x^3-8x^2+5x+14