AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
Therefore AB is 9 cms.
Answer:
The value of MB = 8.4
Step-by-step explanation:
We know that the point of intersection of the Medians of a triangle is called the centroid of a triangle.
Thus,
For the given triangle ΔJKL,
- The point M is the centroid of the triangle.
We also know that the centroid is 2/3 of the distance from each vertex to the midpoint of the opposite side.
Also, each Median is split into two parts such that the longer part is 2 times the length of the smaller part.
In our case,
The median KB is split into two parts such that the longer part KM is 2 times the length of the smaller part MB.
i.e.
KM = 2 MB
Given KM = 16.8
so substitute KM = 16.8 in the equation KM = 2 MB
16.8 = 2 MB
MB = 16.8/2
MB = 8.4
Therefore, the value of MB = 8.4
The answer to your question is D. 512
Text per day: median= 26
1st quartile= 19
3rd quartile=38
Interquartile=19
Daily attendance: median=357.5
1st quartile=298
3rd quartile=422
Interquartile= 124
