Question

The apparent weight of body fully immersed in water is 30 newton and it's weight in air is 96 newton. Calculate the volume of the body.(g=10meter per second and density of water is 100kilogram meter cube)

Answer 1

Point of correction

Density of water is $1000 Kg/m^{3}$ not 100 as provided, it may be typo

Answer:

$0.0066 m^{3}$

Explanation:

Buoyant force of water (Weight difference) is 96-30=66 N

Buoyancy force=$\rho_w g v$ where $\rho_w$ is the density of water, g is acceleration due to gravity whose value is provided as $10 m/s^{2}$ and v is the volume of the body

hence substituting 66 for buoyancy force, $1000 Kg/m^{3}$ for density of water and finding the unknown value of volume, v

66=1000*10*v

$v=0.0066 m^{3}$