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Svetllana [295]
4 years ago
11

The apparent weight of body fully immersed in water is 30 newton and it's weight in air is 96 newton. Calculate the volume of th

e body.(g=10meter per second and density of water is 100kilogram meter cube)
Physics
1 answer:
Lana71 [14]4 years ago
5 0

<u>Point of correction</u>

Density of water is 1000 Kg/m^{3} not 100 as provided, it may be typo

Answer:

0.0066 m^{3}

Explanation:

Buoyant force of water (Weight difference) is 96-30=66 N

Buoyancy force=\rho_w g v where \rho_w is the density of water, g is acceleration due to gravity whose value is provided as 10 m/s^{2} and v is the volume of the body

hence substituting 66 for buoyancy force, 1000 Kg/m^{3} for density of water and finding the unknown value of volume, v

66=1000*10*v

v=0.0066 m^{3}

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We divide the thin rectangular sheet in small parts of height b and length dr. All these sheets are parallel to b. The infinitesimal moment of inertia of one of these small parts is
dI =r^2*dm
where dm =M(b*dr)/(ab)
Now we find the moment of inertia by integrating from -a/2 to a/2
The moment of inertia is
I= \int\limits^{-a/2}_{a/2} {r^2*dm} = M \int\limits^{-a/2}_{a/2} r^2(b*dr)/(ab)=(M/a)(r^3/3) (from (-a/2) toI=(M/3a)(a^3/8 +a^3/8)=(Ma^2)/12 (a/2))



4 0
4 years ago
A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made
olga55 [171]

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

B=\dfrac{\mu_oI}{2\pi r}

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B = 0.000002 T

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(2) Exact formula:

B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }

B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }

B = 0.00000199 T

or

B = 0.000002 T

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4 0
3 years ago
If a wave's third harmonic has a frequency of 24 Hz, what is its
Charra [1.4K]

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

f_n = nf_1

where

f_1 is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

f_3=24 Hz

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz

Now we can also find the frequency of the 6-th harmonic using n = 6:

f_6 = 6 f_1 = 6 (8)=48 Hz

6 0
3 years ago
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ivanzaharov [21]

Answer:

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Explanation:

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victus00 [196]
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3 years ago
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