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mestny [16]
3 years ago
7

If a wave's third harmonic has a frequency of 24 Hz, what is its

Physics
1 answer:
Charra [1.4K]3 years ago
6 0

Answer:

8 Hz, 48 Hz

Explanation:

The standing waves on a string (or inside a pipe, for instance) have different modes of vibrations, depending on how many segments of the string are vibrating.

The fundamental frequency of a standing wave is the frequency of the fundamental mode of vibration; then, the higher modes of vibration are called harmonics. The frequency of the n-th harmonic is given by

f_n = nf_1

where

f_1 is the fundamental frequency

In this problem, we know that the wave's third harmonic has a frequency of

f_3=24 Hz

This means this is the frequency for n = 3. Therefore, we can find the fundamental frequency as:

f_1=\frac{f_3}{3}=\frac{24}{3}=8 Hz

Now we can also find the frequency of the 6-th harmonic using n = 6:

f_6 = 6 f_1 = 6 (8)=48 Hz

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Water enters an ice machine at 55F and leaves as ice at 25F. If the COP of the ice machine is 3.7 during this operation, determi
boyakko [2]

Answer:

The required power is P_i = 0.2692 \ hp

Explanation:

From the question we are told that

   The temperature of the water entering ice machine is T_1 =  55 ^o F

    The temperature of the water leaving is T_2 = 25 ^oF

    The COP of the ice machine is COP= 3.7

    The production rate of an ice  \r m = 15.0 \ lbm /hr

    The energy that needs to removed from each lbm of water at 55 F is E = 169 Btu

Generally the cooling load of the ice machine is mathematically represented as

       \r Q_L =  \r m * E

      \r Q_L =15 * 169

=>  \r Q_L = 2535 \ Btu/h

Generally the COP of the ice machine is mathematically represented as

       COP =  \frac{\r Q_L}{P_i}

Here P_i is the net power  input needed to successfully run the ice machine

So  

     3.7 =  \frac{2535}{P_i}

=>   P_i = 685 \  Btu/h

Converting to horsepower

      P_i = \frac{685}{2545}

=>   P_i = 0.2692 \ hp

     

3 0
3 years ago
A 3 column table with 5 rows labeled table A. The first column is labeled voltage in volts with entries 1.0, 5.0, 10, 20, 50. Th
Volgvan

Answer:

0.25A

1.0A

2.5A

Explanation:

this is only for the calculated current column on edge

6 0
4 years ago
Read 2 more answers
A 600-kg car accelerates from rest to 10 m/s^2. What is the force on the car?
iris [78.8K]

Answer:

60000 newtons

Explanation:

Force=mass × acceleration

60000

3 0
3 years ago
Two speakers face each other, and they each emit a sound of wavelength λ. One speaker is 180∘ out of phase with respect to the o
kolbaska11 [484]
The question ask to calculate and choose among the following is the distance of the microphone from the left - most speaker  in order to pick up the loudest  sound and the best answer would be letter C. I hope you are satisfied with my answer and feel free to ask for more if you have questions and further clarifications 
4 0
3 years ago
Una persona y su perro se encuentran inicialmente en reposo y paradas arriba de una caja que está apoyada sobre un piso rugoso.
alexandr1967 [171]

Answer:

La masa de la mascota es de 11,24 kg.

Explanation:

Dado que la masa total de = 80 kg

Tenemos

Fuerza de fricción = 80 kg × 9.81 × 0.3 = 235.44 N

La mascota salta horizontalmente con una velocidad, v, de 6.0 m / s para dar un movimiento de 1 m a la caja de masa y a la persona

Trabajo realizado por el salto de la mascota = (80 - m) × 9.81 × 0.3

La energía del movimiento del perro = 1/2 × m × v² = Trabajo realizado al saltar de la mascota

1/2 × m × 6² = (80 - m) × 9.81 × 0.3

20943 · m = 235440

m = 235440/20943 = 11,24 kg

5 0
4 years ago
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