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cupoosta [38]
3 years ago
15

A straight wire of length 0.53 m carries a conventional current of 0.2 amperes. What is the magnitude of the magnetic field made

by the current at a location 2.0 cm from the wire? Use both the exact formula and the approximate formula to calculate the field. (a) result using exact formula
Physics
1 answer:
olga55 [171]3 years ago
4 0

Explanation:

It is given that,

Length of wire, l = 0.53 m

Current, I = 0.2 A

(1.) Approximate formula:

We need to find the magnitude of the magnetic field made by the current at a location 2.0 cm from the wire, r = 2 cm = 0.02 m

The formula for magnetic field at some distance from the wire is given by :

B=\dfrac{\mu_oI}{2\pi r}

B=\dfrac{4\pi \times 10^{-7}\times 0.2\ A}{2\pi \times 0.02\ m}

B = 0.000002 T

B=10^{-5}\ T

(2) Exact formula:

B=\dfrac{\mu_oI}{2\pi r}\dfrac{l}{\sqrt{l^2+4r^2} }

B=\dfrac{\mu_o\times 0.2\ A}{2\pi \times 0.02\ m}\times \dfrac{0.53\ m}{\sqrt{(0.53\ m)^2+4(0.02\ m)^2} }

B = 0.00000199 T

or

B = 0.000002 T

Hence, this is the required solution.

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Answer:

13 meters

Explanation:

Step one:

given

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Required

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The total distance can be computed by summing up the 3 meter North distance traveled and the 10 meter south distance traveled

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3 years ago
A dentist uses a concave mirror (focal length 2.5 cm) to examine some teeth. If the distance from the object to the mirror is 1.
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Answer:

2.28

Explanation:

From mirror formula,

1/f = 1/u+1/v .......... Equation 1

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make v the subject of the equation,

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Given: f = 2.5 cm, u = 1.4 cm

Substitute into equation 2

v = 2.5(1.4)/(1.4-2.5)

v = 3.5/-1.1

v = -3.2 cm.

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Given: v = 3.2 cm, u = 1.4 cm

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3 years ago
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Answer:

Explanation:

Given

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2 years ago
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Cadences.

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