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Answer:
Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water <em><u>to the same extent</u></em> by adding 1 mol of to 1 kg of water.
Explanation:
1) Moles of NaCl ,
Mass of water = m= 1 kg = 1000 g
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute(NaCl)=
The vapor pressure for the NaCl solution at 17.19 Torr.
2) Moles of sucrose ,
Mass of water = m = 1 kg = 1000 g
Moles of water =
Vapor pressure of the solution =
Vapor pressure of the pure solvent that is water =
Mole fraction of solute ( glucose)=
The vapor pressure for the glucose solution at 17.19 Torr.
p = p' = 17.19 Torr
Adding 1 mol of NaCl to 1 kg of water lower the vapor pressure of water to the same extent by adding 1 mol of to 1 kg of water.
Answer:
Explanation:
The Rydberg equation gives the wavelength λ for the transitions:
where
R= the Rydberg constant (1.0974 ×10⁷ m⁻¹) and
Data:
λ = 657 nm
Calculation: