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aev [14]
3 years ago
9

Give the number of significant figures indicated. 6.695

Chemistry
1 answer:
iris [78.8K]3 years ago
8 0

Answer:

There are 4 significant figures

Explanation:

Any number that isn’t 0 is significant. Example:765.Any number even if it’s 0 is significant if it’s after the decimal.example:5.00. I believe if the 0 is at the beginning of the number it’s significant aswell.example:086. 0 isn’t significant if it’s in the middle like this: 306

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Heat is transferred in there ways wat and wat ???​
Tamiku [17]

Answer:

Radiation

Conduction

Convection

Explanation:

<u>Radiation:</u> Transfer of heat by electromagnetic rays (Example: A microwave heating food)

<u>Conduction:</u> Transfer of heat energy from one object to another through direct contact (Example: Getting out of bed and your warm feet touch cold tile, making the tile warm and your feet cold)

<u>Convection:</u> Movement of heat by a fluid such as air or water (Example: A convectional oven works by heating the air inside the oven to evenly cook food)

Hope this helps!

4 0
2 years ago
*HELP*
Lina20 [59]
Displcement reaction. metal added to solutions containing metal that is less reactive would have visible reaction while less reactive metal will have no visible reaction. Eg, if copper is added to Mgcl2 andZnCl2, there will be no visible reaction. If Mg is added to CuCl2, blue solution will fade to form colourless solution and a reddish brown ppt of Cu will be formed.
5 0
3 years ago
In what sequence do electrons fill the atomic orbitals within a sub level
harina [27]

Each orbital must contain a single electron before any orbital contains two electrons.

3 0
3 years ago
Rewrite each equation below with the delta h value included with either the reactants or he products , and identify the reaction
grin007 [14]
I will take a stab at it, but there are not equations, did you forget them?
5 0
3 years ago
A piece of copper alloy with a mass of 85.0 g is heated from 30. °C to 45 °C. In the process, it absorbs 523 J of energy as heat
Ne4ueva [31]

Answer:

410.196 J/[kg*°C].

Explanation:

1) the equation of the energy is: E=c*m*(t₂-t₁), where E - energy (523 J), c - unknown specific heat of copper, m - mass of this copper [kg], t₂ - the final temperature, t₁ - initial temerature;

2) the specific heat of copper is:

c=\frac{E}{m*(t_2-t_1)}; \ => \ c=\frac{523}{0.085*(45-30)}=\frac{523}{1.275}=410.196[\frac{J}{kg*C}].

6 0
3 years ago
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