1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leviafan [203]
3 years ago
11

If a certain battery supplies 1.0×108 electrons per second to the negative terminal and the battery contains 7.00 moles of elect

rolytic solution (which means the solution contains 7.00 moles of HSO4), what fraction of the solution undergoes a chemical reaction each second
Chemistry
1 answer:
Verdich [7]3 years ago
3 0

Answer:

The answer to the question is

Fraction of solution in reaction = 1.18 × 10⁻¹⁷

Explanation:

The reaction is as follows

H₂SO₄ ⇆ H⁺ + HSO₄⁻

Negative electrode

Pb +  HSO₄⁻ ⇆ PbSO₄ + H⁺ + 2e⁻

That is one mole of H₂SO₄ produces 2 moles of electtrons to the negative electrode

number of electrons in one mole of electrons = Avogadro's number =6.02×10²³

Therefore 7 moles will produce 14 moles of electtrons

Total number of electrons = 14 × 6.02×10²³ = 8.428×10²⁴ electrons

Fraction of electron produced = Fraction of solution in chemical reaction

= 1.0×10⁸÷8.428×10²⁴ = 1.18 × 10⁻¹⁷

Fraction of solution in reaction = 1.18 × 10⁻¹⁷

You might be interested in
Which elements in the periodic table are metalloids or have semimetallic properties?
inessss [21]
B, As only are metalloids or have semimetallic properties.
3 0
3 years ago
What is an substance
lora16 [44]
<span>a particular kind of matter with uniform properties.

</span>
8 0
3 years ago
Read 2 more answers
2. A rock occupies a volume of 20 cm and has a mass of 54 grams. Find the density of<br> this rock.
vredina [299]
The answer is 2.7gm/cm^3 . Density is mass divided by volume .
6 0
3 years ago
Write the condensed nd structural formulas as well as the names for all isomers of C3H5Cl3.
Sergio039 [100]

Answer:

1) 1,1,1-trichloropropane

2) 1,1,2-trichloropropane

3) 1,2,2-trichloropropane

4) 1,2,3-trichloropropane

Explanation:

For this question, we must remember that isomers are molecules that have the <em>same formula but different structure</em>s. For the formula C_3H_5Cl_3 we can draw a <u>linear chain of three carbons</u> and change the position of the chlorine atoms in the carbon chain.

With this in mind, if we put all the chlorine atoms on the same carbon we will get <u>1,1,1-trichloropropane</u>. If we change an atom from chlorine to carbon 2 we will obtain <u>1,1,2-trichloropropane</u>. If we move another chlorine atom to carbon two we will get <u>1,2,2-trichloropropane</u>. Finally, if we put a chlorine atom in each carbon we will obtain <u>1,2,3-trichloropropane</u>.

See figure one for further explanations

I hope it helps!

4 0
3 years ago
When your grandparents were growing up, they ate
Kryger [21]
It is fresher because of new transportation techniques and refrigerated trailers.
5 0
3 years ago
Other questions:
  • A compound contains 39.0% potassium, 1.01% hydrogen, 12.0% carbon and 47.9% oxygen. Find its empirical formula
    11·1 answer
  • Deserts are increasing world wide. This is known as
    15·1 answer
  • What is the solution to the problem expressed to he correct number of significant figures? 12.0/7.11
    15·1 answer
  • The reaction below is at dynamic equilibrium. mc004-1.jpg Which statement is true for the equilibrium system? The concentration
    13·2 answers
  • Which statement about spontaneous and non spontaneous processes is correct?
    15·1 answer
  • 1. Household bleach (NaOCl) is really a solution of sodium hypochlorite in water. It is made by reacting chlorine gas and sodium
    9·1 answer
  • Which functional group is found in an amine?
    10·2 answers
  • MAX TEN MINUTES PLZZZZZ HURRY
    13·1 answer
  • How many moles of hydrogen, H2, are needed to react with 6.0 moles of nitrogen, N2?
    15·1 answer
  • The melting point of the sample is
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!