Answer:
The correct option is A.
Step-by-step explanation:
Domain:
The expression in the denominator is x^2-2x-3
x² - 2x-3 ≠0
-3 = +1 -4
(x²-2x+1)-4 ≠0
(x²-2x+1)=(x-1)²
(x-1)² - (2)² ≠0
∴a²-b² =(a-b)(a+b)
(x-1-2)(x-1+2) ≠0
(x-3)(x+1) ≠0
x≠3 for all x≠ -1
So there is a hole at x=3 and an asymptote at x= -1, so Option B is wrong
Asymptote:
x-3/x^2-2x-3
We know that denominator is equal to (x-3)(x+1)
x-3/(x-3)(x+1)
x-3 will be cancelled out by x-3
1/x+1
We have asymptote at x=-1 and hole at x=3, therefore the correct option is A....
Answer:
There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.
There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.
Students in Grade 8 are more likely to be members of the band.There are 18 students in Grade 7, 10 are in band, so 10/18 = 0.56 are in band.
There are 12 students in Grade 8, 10 are in band, so 10/12 = 0.83 are in band.
Students in Grade 8 are more likely to be members of the band.
Answer:
it is B:) Have a great day!
Answer:
h=7
Step-by-step explanation:
may be rewritten as
as adding a negative is the same as subtracting a positive.
To solve, add 3 to both sides.
So take 112 and multiply it by 7, 7x112 = 784.
