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Nat2105 [25]
3 years ago
12

C31H64 +4702 — 31C02+32H20

Chemistry
1 answer:
SVETLANKA909090 [29]3 years ago
4 0

Answer:

1504g of oxygen was consumed

Explanation:

C31H64 + 4702 —> 31C02+ 32H20

From the equation, we see clearly that 47moles of O2 was consumed in the reaction.

Molar Mass of O2 = 32g/mol

Number of mole of O2 = 47moles

Mass conc. Of O2 = number of mole x molar Mass

Mass conc. Of O2 = 47 x 32 = 1504g

Therefore, the mass of oxygen consumed in the reaction is 1504g.

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What school objects in a class have organic compounds
Elenna [48]

mostly anything


like wood carpet

4 0
3 years ago
If you have a volume of 10.5 mL and a mass of 100. kg, what is the density?
erma4kov [3.2K]

Answer:

9.52 kg/mL

Explanation:

Density = mass/ Volume

= 100 kg/ 10.5 mL

= 9.523809524 kg/mL

OR

100 kg = 100 × 10^3 g

》Density = 100 × 10^3 g/ 10.5 mL

= 9523.809524 g/mL

3 0
3 years ago
Read 2 more answers
What volume of 2.0 NaOH is required to neutralize 25.0 ml of 2.70 N H2SO4?<br>​
Viktor [21]

Write the equation for the reaction and balance it. In this case the equation is: 2NaOH + H2SO4 → Na2SO4 + 2H2O

Convert the given amount to moles. Molarity, “M” is moles per liter. The given amount is 25 ml of 1.2 M H2SO4. Since Molarity uses Liters, the volume must be converted from ml to L.

Use the mole ratio in this case 2 moles of NaOH to ! mole of H2SO4

Convert the moles to the required units. In this case the required units are grams. The formula weight in grams er mole.

25 ml H2SO4 * 1L/1000 ml * 1.2 Moles/L * 2 moles NaOH/1 mole H2SO4 * 40 g NaOH/ 1 Mole NaOH

Perform these calculations and you have the answer! Timothy, When doing homework, the answer is NOT the important thing, the METHOD is! These 4 steps, combined with required changes in units will sove ANY stoichiometric problem easily.

6 0
3 years ago
What object has a mass of 10 grams and a volume of 2 mL
Elena-2011 [213]

Answer:

Destiny = 5 g/ml

Explanation:

The formula for density is d=

Knowing this, divide your mass by volume:

10 g / 2 ml = 5 g/ml

Final answer:

Destiny = 5 g/ml

3 0
3 years ago
g Consider the reaction when aqueous solutions of potassium hydroxide and ammonium bromide are combined. The net ionic equation
vichka [17]

Answer:

K^+(aq) + Br^-(aq) -----> KBr(aq)

Explanation:

The net ionic equation shows the actual reaction that occurs in the system. The molecular reaction equation includes the spectator ions but the net ionic equation does not include the spectator ions.

Spectator ions do not participate in the main reaction going on in the system.

Hence, for the reaction of potassium hydroxide and ammonium bromide, we have;

K^+(aq) + Br^-(aq) -----> KBr(aq)

8 0
4 years ago
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