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Nat2105 [25]
2 years ago
12

C31H64 +4702 — 31C02+32H20

Chemistry
1 answer:
SVETLANKA909090 [29]2 years ago
4 0

Answer:

1504g of oxygen was consumed

Explanation:

C31H64 + 4702 —> 31C02+ 32H20

From the equation, we see clearly that 47moles of O2 was consumed in the reaction.

Molar Mass of O2 = 32g/mol

Number of mole of O2 = 47moles

Mass conc. Of O2 = number of mole x molar Mass

Mass conc. Of O2 = 47 x 32 = 1504g

Therefore, the mass of oxygen consumed in the reaction is 1504g.

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<u>Now the volume is given =78.4 therefore,</u>

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