Data Given:
Initial Volume = V₁ = 36.7 L
Initial Pressure = P₁ = 145 kPa
Initial Temperature = T₁ = 65 °C + 273 = 338 K
Final Volume = V₂ = ?
Final Pressure = P₂ = 101.325 kPa (Standard Pressure)
Final Temperature = T₂ = 273 K (Standard Temperature)
Formula used:
As number of moles are constant, so Ideal Gas equation in following form is used,
P₁ V₁ / T₁ = P₂ V₂ / T₂
Solving for V₂,
V₂ = P₁ V₁ T₂ / T₁ P₂
Putting Values,
V₂ = (145 kPa × 36.7 L × 338 K) ÷ (273 K × 101.325 kPa)
V₂ = 1798667 ÷ 27661.25
V₂ = 65.02 L
Density = <u>mass
</u> volume
<u>
</u>For the sake of explanation, let's pretend the mass is 2g and the volume is 1 ml
<u>
</u>Density = <u>2 g </u>= 2 g/ml
<u /> 1 ml
Now if we increase the volume, and leave the mass the same then mass is still 2g, but we can increase the volume to 2 ml
Density = <u>2 g </u> = 1 g/ml<u>
</u> 2 ml
<u>
</u>Therefore we can say that <em>if volume increases and mass stays the same, then density will decrease</em>.<u>
</u>
Answer: the sum of the partial pressures of the individual gases.
Explanation:
According to Dalton's Law of partial pressure, the total pressure of a mixture of gases is equal to the sum of the partial pressures which each individual gas would exert if it were confined alone in the volume occupied by the mixture.
Hence, Ptotal = P1+ P2
where Ptotal is the total pressure
P1 and P2 are the partial pressures exerted seperately by the individual gases 1 and 2 that make up the mixture.
Answer: A property closely related to an atom's mass number is its atomic mass. The atomic mass of a single atom is simply its total mass and is typically expressed in atomic mass units or amu. By definition, an atom of carbon with six neutrons, carbon-12, has an atomic mass of 12 amu.
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