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gladu [14]
3 years ago
5

Some students were investigating the

Chemistry
2 answers:
AleksAgata [21]3 years ago
6 0

Answer:

Isaac is the best

Explanation:

I find a friend to help you

nordsb [41]3 years ago
5 0

Answer:

I am a grade six student but I am very interested in chemistry

Explanation:

I sorry but this is NOT chemistry

You might be interested in
Determine the [H3O+] in a 0.265 M HClO solution. The Ka of HClO is 2.9 × 10-8.
dexar [7]

8.8 × 10-5 M is the  [H3O+] concentration in 0.265 M HClO solution.

Explanation:

HClO is a weak acid and does not completely dissociate in water as ions.

the equation of dissociation can be written and ice table to be formed.

 HClO +H2O ⇒ ClO- + H3O+

I  0.265                0        0

C  -x                    +x     +x

E  0.265-x          +x      +x

Now applying the equation of Ka, where Ka is given as 2.9 × 10-8.

Ka = \frac{[ClO-][H3O+]}{[HClO]}

2.9 × 10^-8 = \frac{[x] [x]}{[0.265-x]}

x^{2} = 7.698 x10^{-9}

x = 8.8 × 10-5 M

The hydronium ion concentration is 8.8 × 10-5 M  in 0.265 M solution of HClO.

8 0
3 years ago
When ammonium chloride is dissolved in water, the beaker gets cold. Which type of reaction does this describe
gulaghasi [49]

Answer:

B

Explanation:

i think with exothermic reactions heat is released

this is what i looked up

hope this helps i took chem last year and think this is what i learned

7 0
3 years ago
Q: A 25.5 mL aliquot of HCl (aq) of unknown concentration was titrated with 0.113 M NaOH (aq). It took 51.2 mL of the base to re
blondinia [14]
M ( HCl ) = ?

V ( HCl ) = 25.5 mL in liters : 25.5 / 1000 => 0.0255 L

M ( NaOH ) = 0.113 M

V ( NaOH ) = 51.2 mL / 1000 => 0.0512 L

number of moles NaOH:

n = M x V

n = 0.113 x <span> 0.0512 => 0.0057856 moles of NaOH

mole ratio:

</span><span>HCl + NaOH = NaCl + H2O
</span><span>
1 mole HCl -------------- 1 mole NaOH
( moles HCl ) ----------- </span><span> 0.0057856 moles NaOH
</span>
(moles HCl ) = <span> 0.0057856 x 1 / 1
</span>
= <span> 0.0057856 moles of HCl
</span>
M ( HCl ) = n / V

M =  0.0057856 / <span>0.0255
</span>
= 0.227 M

Answer A

hope this helps!

4 0
3 years ago
Read 2 more answers
Could someone plz help me? :(
kvv77 [185]

Answer:

I think it's B " Constraints are more important than criteria ".

3 0
3 years ago
If you combine 27.1 g of a solute that has a molar mass of 27.1 g/mol with 100.0 g of a solvent, what is the molality of the res
baherus [9]

<u>Answer:</u> The molality of the solution is 0.1 m.

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

Molality=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ in grams}}

Where,

m_{solute} = Given mass of solute = 27.1 g

M_{solute} = Molar mass of solute = 27.1 g/mol

W_{solvent} = Mass of solvent = 100 g

Putting values in above equation, we get:

\text{Molality of solution}=\frac{27.1\times 1000}{27.1\times 100}\\\\\text{Molality of solution}=0.1m

Hence, the molality of the solution is 0.1 m.

8 0
3 years ago
Read 2 more answers
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