Remember this:
1) n is principal quantum number and represents the energy level.
2) l is the second quantum number and represent the type of orbital.
3) l can take values from 0 to n - 1
4) each number of l is associated with a type of orbital. This table shows the equivalence:
l number type of orbital
0 s
1 p
2 d
3 f
With that, you can tell that n = 2 permits l = 0 and 1, which is orbitals s and p.
Therefore, the answer is the option D) s, p.
Answer:
<h3>Which of the following is the correct definition for electronegativity</h3>
<h3>А. The amount of energy to attract or bond electrons</h3>
<span>293 grams
The formula for the wavelength of a massive particle is
λ = h/p
where
λ = wavelength
h = Plank constant (6.626070040Ă—10^â’34 J*s)
p = momentum (mass times velocity)
So let's solve for momentum and from there get the mass
λ = h/p
λp = h
p = h/λ
Substitute known values and solve
p = 6.626070040Ă—10^â’34 J*s/3.45Ă—10^-34 m
p = 1.92 J*s/m
Since momentum is the product of mass and velocity, we have
p = M * V
p/V = M
So substitute again, and solve.
p/V = M
1.92 J*s/m / 6.55 m/s = M
1.92 kg*m/s / 6.55 m/s = M
1.92 kg*m/s / 6.55 m/s = M
0.293 kg = M
So the mass is 293 grams</span>
- From the general law of gases: PV = nRT,
where P is the pressure (atm),
V is the volume (L),
n is the number of moles,
R is the general gas constant (8.314 L.atm/mol.K),
T is the temperature in Kelvin
- at constant volume of the gas: P1T2 = P2T1
P1 = 3.20 atm, T1 = 300 K, T2 = 290 K, P2 = ??
(3.20 atm)(290 K) = P2(300 K)
P2 = (3.20 atm)(290 K)/ (300 K) = 3.093 atm
